访问具有谓词属性的XML元素,该属性在PHP中动态更新


Access XML element with predicate attribute that updates dynamically in PHP

这里是新手。PHP中的xpath()函数出现问题。

XML文件(data.XML):

<?xml version="1.0" ?> 
<menu>
<food type="Pizza">
    <item>
            <name>  Tomato &amp; Cheese  </name>
            <small price="5.50"/>
            <large price="9.75"/>
    </item>
    <item>
            <name>   Onions </name>
            <small price="6.85"/>
            <large price="10.85"/>
    </item>
</food>
</menu>

PHP代码:

   <?php 
   $xml = simplexml_load_file("data.xml");
   $types = $xml->xpath("/menu/food/@type");
   foreach($types as $type){
      echo("<h1>$type</h1>");
      $menu = $xml->xpath("/menu/food[@type=$type]");     
      echo("<ul>");
      foreach($menu as $submenu){
         echo ("<li>$submenu</li>");
      }
      echo("</ul>");
   } 
   ?>

我有很多种食物。我想按顺序访问它们及其子类型。我上面的方法有问题。我好像找不到它。以下是我的预期输出。如何使用xpath()来实现这一点?

预期输出:

披萨

=>番茄;奶酪

=>洋葱

=>

FOO-

=>BAR

您只需要一个xpath查询,如下所示:

$xml = simplexml_load_file("data.xml");
// Get food items and iterate over them
$foods = $xml->xpath("/menu/food");
foreach($foods as $food){
    // print type attribute
    echo("<h1>{$food["type"]}</h1>");
    // Iterate over food items and print their names
    echo("<ul>");
    foreach($food->item as $item){
        echo ("<li>$item->name</li>");
    }
    echo("</ul>");
}

拥有这个xml:

<?xml version="1.0" ?>
<menu>
<food type="Pizza">
    <item>
            <name>Tomato &amp; Cheese</name>
            <small price="5.50"/>
            <large price="9.75"/>
    </item>
    <item>
            <name>Onions</name>
            <small price="6.85"/>
            <large price="10.85"/>
    </item>
</food>
<food type="Pasta">
    <item>
            <name>Bolognese</name>
            <small price="5.50"/>
            <large price="9.75"/>
    </item>
    <item>
            <name>Carbonara</name>
            <small price="6.85"/>
            <large price="10.85"/>
    </item>
</food>
</menu>

上述代码将产生:

<h1>Pizza</h1>
<ul>
  <li>Tomato & Cheese</li>
  <li>Onions</li>
</ul>
<h1>Pasta</h1>
<ul>
  <li>Bolognese</li>
  <li>Carbonara</li>
</ul>

尝试更改

  $menu = $xml->xpath("/menu/food[@type=$type]");     
  echo("<ul>");
  foreach($menu as $submenu){
     echo ("<li>$submenu</li>");
  }

  $menu = $xml->xpath("/menu/food[@type='$type']/item/name");     
  echo("<ul>");
  foreach($menu as $submenu){
     echo ("<li>$submenu</li>");
  }