我一直在做一些研究，但似乎在这里找不到问题。
<body>
<?php
if($_POST){
// get latitude, longitude and formatted address
$data_arr = geocode($_POST['address']);
// if able to geocode the address
if($data_arr){
$latitude = $data_arr[0];
$longitude = $data_arr[1];
$formatted_address = $data_arr[2];
?>
<!-- google map will be shown here -->
<div id="gmap_canvas">Loading map...</div>
<div id='map-label'>Map shows approximate location.</div>
<!-- JavaScript to show google map -->
<script type="text/javascript" src="http://maps.google.com/maps/api/js"></script>
<script type="text/javascript">
function init_map() {
var myOptions = {
zoom: 14,
center: new google.maps.LatLng(<?php echo $latitude; ?>, <?php echo $longitude; ?>),
mapTypeId: google.maps.MapTypeId.ROADMAP
};
map = new google.maps.Map(document.getElementById("gmap_canvas"), myOptions);
marker = new google.maps.Marker({
map: map,
position: new google.maps.LatLng(<?php echo $latitude; ?>, <?php echo $longitude; ?>)
});
infowindow = new google.maps.InfoWindow({
content: "<?php echo $formatted_address; ?>"
});
google.maps.event.addListener(marker, "click", function () {
infowindow.open(map, marker);
});
infowindow.open(map, marker);
}
google.maps.event.addDomListener(window, 'load', init_map);
</script>
<?php
// if unable to geocode the address
}else{
echo "No map found.";
}
}
?>
<div id='address-examples'>
<div>Address examples:</div>
<div></div>
<div></div>
</div>
<!-- enter any address -->
<form action="" method="post">
<input type='text' name='address' placeholder='Enter any address here' />
<input type='submit' value='Geocode!' />
</form>
<?php
// function to geocode address, it will return false if unable to geocode address
function geocode($address){
// url encode the address
$address = urlencode($address);
// google map geocode api url
$url = "http://maps.google.com/maps/api/geocode/json?address={$address}";
// get the json response
$resp_json = file_get_contents($url);
// decode the json
$resp = json_decode($resp_json, true);
// response status will be 'OK', if able to geocode given address
if($resp['status']=='OK'){
// get the important data
$lati = $resp['results'][0]['geometry']['location']['lat'];
$longi = $resp['results'][0]['geometry']['location']['lng'];
$formatted_address = $resp['results'][0]['formatted_address'];
// verify if data is complete
if($lati && $longi && $formatted_address){
// put the data in the array
$data_arr = array();
array_push(
$data_arr,
$lati,
$longi,
$formatted_address
);
return $data_arr;
}else{
return false;
}
}else{
return false;
}
}
?>
</body>
//在下面的行中，我得到错误消息"意外令牌？"
center: new google.maps.LatLng(<?php echo $latitude; ?>,<?php echo $longitude; ?>),
很抱歉，如果这还不够，这是我第一次使用谷歌地图。
我发现我的代码不是问题所在。我需要更换
script type="text/javascript"src="http://maps.google.com/maps/api/js">
至
script type="text/javascript"src="https://maps.google.com/maps/api/js">
出于某种原因，浏览器需要安全地访问这个src链接，而我在http上没有"s"。一旦我添加了S，它就开始在所有浏览器上运行。