错误blob上载警告:fopen(C:examplep mpphp4FC4.tmp):无法打开流:没有这样的


error blob uploading Warning: fopen(C:xampp mpphp4FC4.tmp): failed to open stream: No such file or directory

我正在尝试用BLOB创建多个上传。

上面的代码给了我以下错误

警告:fopen(C:''examplep''tmp''php4FC4.tmp):无法打开流:没有这样的文件或目录

PHP脚本

$jumlah_file = count($_FILES['userfile']['name']);
$path = pathinfo($_SERVER['PHP_SELF']);
for ($i = 0; $i < $jumlah_file; $i++)
{
    $tmp_file = $_FILES['userfile']['tmp_name'][$i];
    $filetype = $_FILES['userfile']['type'][$i];
    $filesize = $_FILES['userfile']['size'][$i];
    $filename = $_FILES['userfile']['name'][$i];
    $destination = $path['dirname'].
    '/data/'.$filename;
    move_uploaded_file($tmp_file, $_SERVER['DOCUMENT_ROOT'].$destination);
}
$fp = fopen($tmp_file, 'r'); // ERROR LINE
$content = fread($fp, filesize($tmp_file));
$content = addslashes($content);
fclose($fp);
if (!get_magic_quotes_gpc())
{
    $fileName = addslashes($filename);
}
$query = mysql_query("INSERT INTO `konveksi`.`foto` (`id_foto`, `id_daftar`, `id_pesanan`, `foto`) VALUES (NULL, '15', '1','$content');");
mysql_query($query) or die('Error, query failed');

我该怎么办?如果这是一个愚蠢的问题,请原谅,我是PHP的新手。

您已经使用move_uploaded_file($tmp_file, $_SERVER['DOCUMENT_ROOT'].$destination);将文件移动到$fp = fopen($tmp_file, 'r');之前。之后,文件将位于其他位置。正确的代码是:

$jumlah_file = count($_FILES['userfile']['name']);
$path = pathinfo($_SERVER['PHP_SELF']);
for ($i = 0; $i < $jumlah_file; $i++)
{
    $tmp_file = $_FILES['userfile']['tmp_name'][$i];
    $filetype = $_FILES['userfile']['type'][$i];
    $filesize = $_FILES['userfile']['size'][$i];
    $filename = $_FILES['userfile']['name'][$i];
    $destination = $path['dirname'].
    '/data/'.$filename;
    $fp = fopen($tmp_file, 'r');
    $content = fread($fp, filesize($tmp_file));
    $content = addslashes($content);
    fclose($fp);
    move_uploaded_file($tmp_file, $_SERVER['DOCUMENT_ROOT'].$destination);
}
if (!get_magic_quotes_gpc())
{
    $fileName = addslashes($filename);
}
$query = mysql_query("INSERT INTO `konveksi`.`foto` (`id_foto`, `id_daftar`, `id_pesanan`, `foto`) VALUES (NULL, '15', '1','$content');");
mysql_query($query) or die('Error, query failed');