在PHP中将Object转换为JSON，将JSON转换为Object(类似Java的Gson库）

这样就可以了！

// convert object => json
$json = json_encode($myObject);
// convert json => object
$obj = json_decode($json);

这里有一个的例子

$foo = new StdClass();
$foo->hello = "world";
$foo->bar = "baz";
$json = json_encode($foo);
echo $json;
//=> {"hello":"world","bar":"baz"}
print_r(json_decode($json));
// stdClass Object
// (
//   [hello] => world
//   [bar] => baz
// )

如果希望输出为数组而不是对象，请将true传递给json_decode

print_r(json_decode($json, true));
// Array
// (
//   [hello] => world
//   [bar] => baz
// )    

关于json_encode（）的更多信息

另请参阅：json_decode（）

为了使大型应用程序具有更大的可扩展性，请使用带有封装字段的oop样式。

简单的方法：-

  class Fruit implements JsonSerializable {
        private $type = 'Apple', $lastEaten = null;
        public function __construct() {
            $this->lastEaten = new DateTime();
        }
        public function jsonSerialize() {
            return [
                'category' => $this->type,
                'EatenTime' => $this->lastEaten->format(DateTime::ISO8601)
            ];
        }
    }

echo json_encode（new Fruit（））//输出：

{"category":"Apple","EatenTime":"2013-01-31T11:17:07-0500"}

PHP上的真实Gson：-

1. http://jmsyst.com/libs/serializer
2. http://symfony.com/doc/current/components/serializer.html
3. http://framework.zend.com/manual/current/en/modules/zend.serializer.html
4. http://fractal.thephpleague.com/-仅序列化

json_decode($json, true); 
// the second param being true will return associative array. This one is easy.

PHP8代码：

class foo{
    function __construct(
        public $bar,
        protected $bat,
        private $baz,
    ){}
    function getBar(){return $this->bar;}
    function getBat(){return $this->bat;}
    function getBaz(){return $this->baz;}
}
//Create Object
$foo = new foo(bar:"bar", bat:"bat", baz:"baz");
//Object => JSON
$fooJSON = json_encode(serialize($foo));
print_r($fooJSON);
// "O:3:'"foo'":3:{s:3:'"bar'";s:3:'"bar'";s:6:'"'u0000*'u0000bat'";s:3:'"bat'";s:8:'"'u0000foo'u0000baz'";s:3:'"baz'";}"
// Important. In order to be able to unserialize() an object, the class of that object needs to be defined.
#   More information here: https://www.php.net/manual/en/language.oop5.serialization.php
//JSON => Object
$fooObject = unserialize(json_decode($fooJSON));
print_r($fooObject);
//(
#    [bar] => bar
#    [bat:protected] => bat
#    [baz:foo:private] => baz
# )
//To use some functions or Properties of $fooObject
echo $fooObject->bar;
// bar
echo $fooObject->getBat();
// bat
echo $fooObject->getBaz();
// baz

我做了一个方法来解决这个问题。我的方法是：

1-创建一个抽象类，该类具有使用Regex将对象转换为数组（包括私有属性）的方法。2-将返回的数组转换为json。

我使用这个抽象类作为我所有域类的父类

等级代码：

namespace Project'core;
abstract class AbstractEntity {
    public function getAvoidedFields() {
        return array ();
    }
    public function toArray() {
        $temp = ( array ) $this;
        $array = array ();
        foreach ( $temp as $k => $v ) {
            $k = preg_match ( '/^'x00(?:.*?)'x00(.+)/', $k, $matches ) ? $matches [1] : $k;
            if (in_array ( $k, $this->getAvoidedFields () )) {
                $array [$k] = "";
            } else {
                // if it is an object recursive call
                if (is_object ( $v ) && $v instanceof AbstractEntity) {
                    $array [$k] = $v->toArray();
                }
                // if its an array pass por each item
                if (is_array ( $v )) {
                    foreach ( $v as $key => $value ) {
                        if (is_object ( $value ) && $value instanceof AbstractEntity) {
                            $arrayReturn [$key] = $value->toArray();
                        } else {
                            $arrayReturn [$key] = $value;
                        }
                    }
                    $array [$k] = $arrayReturn;
                }
                // if it is not a array and a object return it
                if (! is_object ( $v ) && !is_array ( $v )) {
                    $array [$k] = $v;
                }
            }
        }
        return $array;
    }
}