比方说，我有这个代码：
var i = new GIcon(G_DEFAULT_ICON);
var latlng = new GLatLng(33.013489, -117.140167);
map.setCenter(latlng, 9);
map.panTo(latlng);
var i = new GIcon(G_DEFAULT_ICON);
var latlng = new GLatLng(32.979286, -117.02623);
map.setCenter(latlng, 9);
map.panTo(latlng);
var i = new GIcon(G_DEFAULT_ICON);
var latlng = new GLatLng(32.746319, -117.141449);
map.setCenter(latlng, 9);
map.panTo(latlng);
var i = new GIcon(G_DEFAULT_ICON);
var latlng = new GLatLng(32.758286, -117.125053);
map.setCenter(latlng, 9);
map.panTo(latlng);
如何使用PHP返回列表或仅返回纬度和经度。所以GLatLng() 之间的任何东西
所以我最终会得到一个数组，看起来像这样：
32.758286, -117.125053
32.979286, -117.02623
32.746319, -117.141449
32.758286, -117.125053
preg_match_all('~
(?<='() (?# starts with opening parentheses )
(?P<lat>['d.-]+) (?# then a digit, dot or dash more than one time )
's*,'s* (?# followed by a comma with any number of spaces around )
(?P<lng>['d.-]+) (?# then another digit, dot or dash more than one time )
(?=')) (?# ends with closing parentheses )
~x', $str, $matches);
var_dump($matches);
您可以先找到命名为GLatLng(的开始字符串，然后找到结束字符串)，并取两者之间的值。只要你能找到起始字符串，就重复。
演示：
$result = [];
$start = 'GLatLng(';
$offset = 0;
while (false !== $pos = strpos($buffer, $start, $offset))
{
$offset = $pos + strlen($start);
$result[] = substr($buffer, $offset, strpos($buffer, ')', $offset) - $offset);
}
类似这样的东西：
/* Split the raw input by its newline characters */
$input = explode("'r'n", $rawInput);
$outputStack = array();
foreach ($input as $inputRow)
{
splitRow = explode("new GLatLng(", $inputRow);
if (sizeof(splitRow) > 1)
{
/* if you can split the row into more than one peice, you know what's going to be in splitRow[1]: your lat, long */
array_push($output_stack, str_replace(");", "", splitRow[1]));
}
}