表单未触发javascript onsubmit事件 - Form not triggering javascript onsubmit event

我在我的网站上创建了一个"注册"页面，但当"onsubmit"事件触发时，javascript验证函数似乎不会调用。我已经阅读了这个网站上关于类似问题的帖子，但他们的问题似乎是忘记返回一个布尔值，指示继续执行操作。请注意，这个页面被"包含"在另一个带有php函数"include"的页面中。

<script type="text/javascript">
    function validateForm()  {
        //alert();
        var display = document.getElementById('error');
        var usernameValue = document.getElementById('username').value;
        var passwordValue = document.getElementById('password').value;
        var rptPasswordValue = document.getElementById('rptPassword').value;
        var emailValue = document.getElementById('email').value;
        var aliasValue = document.getElementById('alias').value;
        if (usernameValue != '' && passwordValue != '' && rptPasswordValue != '' && emailValue != '' && aliasValue != '')  {
            if (passwordValue == rptPasswordValue)  {
                if (usernameValue.length > 32 || aliasValue.length > 32)  {
                    displayError("Username or password is too long (Both fields must contain 32 characters or less)");
                } else {
                    if (passwordValue.length > 32 || passwordValue.length < 4)  {
                        displayError("Password must be between 4 and 32 characters in length.");
                    } else {
                        if (emailValue.indexOf('@') == -1 || emailValue.length > 64 || emailValue.length < 6)  {
                            displayError("Please make sure you have entered a valid email. (Emails must be between 6 and 64 characters in length)");
                        } else {
                            if (aliasValue < 3 || aliasValue > 32)  {
                                displayError("Your alias must be between 3 and 32 characters in length.");
                            } else {
                                return true;
                            }
                        }
                    }
                }
            } else {
                displayError("Please make sure both passwords match.");
            }
        } else {
            displayError("Please make sure each field contains a value.");
        }
        return false;
    }
    function displayError(var msg)  {
        document.getElementById('error').innerHTML = msg;
    }
</script>
<h1>Sign Up</h1>
<p>All fields must be filled out in order for an account to be created.</p>
<form onsubmit="return validateForm();" action="register.php" method="post">
    <table>
        <tr>
            <td>
                <p class="txtLabel">Username:</p>
            </td>
            <td>
                <input type="text" class="defaultTxt" tabindex="0"  id="username" name='username'>
            </td>
            <td>
                <p class="txtLabel">Email Address:</p>
            </td>
            <td>
                <input type="text" class="defaultTxt" tabindex="1"  id="email" name='email'>
            </td>
        </tr>
        <tr>
            <td>
                <p class="txtLabel">Password:</p>
            </td>
            <td>
                <input type="password" class="defaultTxt" tabindex="2"  id="password" name='password'>
            </td>
        </tr>
        <tr>
            <td>
                <p class="txtLabel">Repeat Password:</p>
            </td>
            <td>
                <input type="password" class="defaultTxt" tabindex="2"  id="rptPassword" name='rptPassword'>
            </td>
        </tr>
        <tr>
            <td>
                <p class="txtLabel">Nickname/Alias:</p>
            </td>
            <td>
                <input type="text" class="defaultTxt" tabindex="4"  id="alias" name='alias'>
            </td>
        </tr>
    </table>
    <p><b id='error' style='color: red'></b></p><br />
    <input type="submit" value='' name='submit' class="submitBtn">
</form>

请注意，在validateForm函数中，警报用于测试是否调用了该函数，而不是。

有什么想法吗？

function displayError(var msg)  {
        document.getElementById('error').innerHTML = msg;
    }

更换为

function displayError(msg)  {
        document.getElementById('error').innerHTML = msg;
    }

在您的java脚本函数中，您不能像function displayError(var msg)那样编写。

祝你好运。

JavaScript中的错误：

function displayError(var msg)  {
                      ^^^
     document.getElementById('error').innerHTML = msg;
}

方法参数中不需要var关键字。