,我希望有人能帮我
我有两个表wp_wp_pro_quiz_statistic_ref
和wp_wp_pro_quiz_statistic
,它们之间的公共链接是statistic_ref_id
。
想要显示的数据在wp_wp_pro_quiz_statistic
中,我可以使用以下方法获取:
<?php
global $wpdb;
$current_user = wp_get_current_user();
$current_user_statid = $wpdb->get_results( "SELECT * FROM wp_wp_pro_quiz_statistic_ref WHERE user_id = $current_user->ID");
$result = $wpdb->get_results( "SELECT * FROM wp_wp_pro_quiz_statistic WHERE $current_user_statid = statistic_ref_id");
echo "Question:"." "."Points:"."<br><br>";
foreach($result as $row)
{
echo $row->question_id." ".$row->points."<br>";
}
?>
wp_wp_pro_quiz_statistic_ref
存储user_id
和statistic_ref_id
可以使用CCD_ 8或类似的东西来提取用户ID。我不知道如何使用"statistic_ref_id"只显示与wp_wp_pro_quiz_statistic
中statistic_ref_id
的值匹配的行。
更新:
<table border="1" width="500px">
<tr>
<th>Question Number</th>
<th>Clause</th>
<th>Subject</th>
<th>Score</th>
</tr>
<?php
global $wpdb;
$current_user = wp_get_current_user();
$result = $wpdb->get_results( "
SELECT stats.*
FROM wp_wp_pro_quiz_statistic stats
JOIN wp_wp_pro_quiz_statistic_ref refs on stats.statistic_ref_id = refs.statistic_ref_id
WHERE refs.user_id= $current_user->ID ");
foreach($result as $row) {
echo "<tr>
<td>$row->question_id</td>
<td>some clause</td>
<td>some subject</td>
<td>$row->points</td>
</tr>";
}
?>
</table>
<table border="1" width="500px">
<tr><td width="445px">Total Score (Maximum 125)</td><td width="55px">0</td> </tr>
</table>
</body>
</html>
如果我理解你的问题,你应该能够使用SQL联接;像这样的东西:
<?php
global $wpdb;
$current_user = wp_get_current_user();
$result = $wpdb->get_results( "
SELECT stats.*
FROM wp_wp_pro_quiz_statistic stats
JOIN wp_wp_pro_quiz_statistic_ref refs on stats.statistic_ref_id = refs.statistic_ref_id
WHERE refs.user_id= $current_user->ID ");
echo "Question:"." "."Points:"."<br><br>";
foreach($result as $row) {
echo $row->question_id." ".$row->points."<br>";
}
?>