我有一个网站,上面有以下代码片段:
<?php
mysql_connect('localhost','root','password');
mysql_select_db('news');
$id_article = $_GET['newsid'];
$query = mysql_query('SELECT * FROM news WHERE id="$id_article"');
{
echo '<div class="item"><h1><a href="read-news.php?newsid='.$query['id'].'">'.$query['subject'].'</a></h1><br />';
echo $query['full_content'].'<br / >';
echo date('D-M-Y', $query['date']).'<br / >';
echo 'Posted by '.$id_article;
echo '</div>';
}
?>
$id_article
从以前的请求中获取id。$id_article
有效,但$query
无效。$query['***']
仍为空白。我不知道为什么。请帮帮我!非常感谢!
您不会得到查询结果。使用如下:
<?php
mysql_connect('localhost','root','password');
mysql_select_db('news');
$id_article = intval($_GET['newsid']);
$query = mysql_query('SELECT * FROM news WHERE id=' . $id_article);
if (mysql_num_rows($query) > 0)
{
$row = mysql_fetch_assoc($query);
echo '<div class="item"><h1><a href="read-news.php?newsid='.$row['id'].'">'.$row['subject'].'</a></h1><br />';
echo $row['full_content'].'<br / >';
echo date('D-M-Y', $row['date']).'<br / >';
echo 'Posted by '.$id_article;
echo '</div>';
}
?>
提示:使用PDO或mysqli而不是mysql_函数!Mysql函数在新的php版本中被弃用/不受支持!
此外,在传递到您的查询之前,对您的输入进行疗养!
像这样使用
$result = mysql_query($query) or die(mysql_error());
$row = mysql_fetch_array($result) or die(mysql_error());
echo $row['id']. " - ". $row['date'];
您尚未使用mysql_fetch_assoc
。使用如下:
$query = mysql_query('SELECT * FROM news WHERE id=' . $id_article);
$row = mysql_fetch_assoc($query);
if(count($row)>0)
{
echo '<div class="item"><h1><a href="read-news.php?newsid='.$query['id'].'">'.$row['subject'].'</a></h1><br />';
echo $row['full_content'].'<br / >';
echo date('D-M-Y', $row['date']).'<br / >';
echo 'Posted by '.$id_article;
echo '</div>';
}
更改此代码
$query = mysql_query('SELECT * FROM news WHERE id="$id_article"');
{
echo '<div class="item"><h1><a href="read-news.php?newsid='.$query['id'].'">'.$query['subject'].'</a></h1><br />';
echo $query['full_content'].'<br / >';
echo date('D-M-Y', $query['date']).'<br / >';
echo 'Posted by '.$id_article;
echo '</div>';
}
至
$sql = "SELECT * FROM news WHERE id = $id_article";
$query = mysql_query($sql);
while($result = mysql_fetch_assoc($query));
{
echo '<div class="item"><h1><a href="read-news.php?newsid='.$result['id'].'">'.$result['subject'].'</a></h1><br />';
echo $result['full_content'].'<br / >';
echo date('D-M-Y', $result['date']).'<br / >';
echo 'Posted by '.$id_article;
echo '</div>';
}
您的代码中有很多错误mysql_query已折旧使用以下代码并检查错误
<?php
mysql_connect('localhost', 'root', 'password');
$conn = mysql_select_db('news');
$id_article = $_GET['newsid'];
if($query = mysqli_fetch_assoc(mysqli_query($conn,"SELECT * FROM news WHERE id=$id_article"))){
echo '<div class="item"><h1><a href="read-news.php?newsid=' . $query['id'] . '">' . $query['subject'] . '</a></h1><br />';
echo $query['full_content'] . '<br / >';
echo date('D-M-Y', $query['date']) . '<br / >';
echo 'Posted by ' . $id_article;
echo '</div>';
}
?>
试试这个。。
$id_article = $_GET['newsid'];
$query = "SELECT * FROM news WHERE id='$id_article'";
$query1=mysql_query($query);
您应该调用一个函数来获取查询返回的行。您正试图访问$查询而不是行。你的代码应该是这样的:
<?php
mysql_connect('localhost','root','password');
mysql_select_db('news');
$id_article = $_GET['newsid'];
$query = mysql_query('SELECT * FROM news WHERE id="$id_article"');
if ($query) {
$row = mysql_fetch_assoc($query));
echo '<div class="item"><h1><a href="read-news.php?newsid='. $row['id'].'">'. $row['subject'].'</a></h1><br />';
echo $row['full_content'].'<br / >';
echo date('D-M-Y', $row['date']).'<br / >';
echo 'Posted by '.$id_article;
echo '</div>';
} else {
$message = 'Invalid query: ' . mysql_error() . "'n";
$message .= 'Whole query: ' . $query;
die($message);
}
?>
您还可以查看mysql_result()、mysql_fetch_array()、mysql _fetch_row()函数。