我是bootstrap的新手，我需要一些帮助，当用户在"ContactName"TEXTBOX中搜索联系人名称并用-联系人姓名-电话号码-电子邮件地址提前感谢
这是我尝试返回一个值的代码，我需要修改它来返回所有这些树值现在，当我尝试搜索联系人姓名时，它会正确返回，没有任何问题可问，但我不知道如何修改代码以带来3值，就像我在上面提到的
enter code here
**php page: Customer.php**
-------------------------------------------
<?php
$host = "localhost";
$uname = "root";
$pass = "";
$database = "db34218";
$connection=mysql_connect($host,$uname,$pass) or die("connection in not ready <br>");
$result=mysql_select_db($database) or die("database cannot be selected <br>");
if (isset($_REQUEST['query'])) {
$query = $_REQUEST['query'];
$sql = mysql_query ("SELECT ContactName, Telephone, Email FROM customer WHERE ContactName LIKE '%{$query}%'");
$array = array();
while ($row = mysql_fetch_assoc($sql)) {
$array[] = $row['ContactName'];
}
echo json_encode ($array); //Return the JSON Array
}
?>
**html and java page and some php: Customersearch.php**
------------------------------------------------
<body>
.
.
.
<div class="row-fluid">
<div class="span4">
<label>ContactName </label>
<input type="text" name="ContactName" value="<?php echo $row_Recordset_QuoteCustomer['ContactName']?>" data-provide="typeahead" class="typeahead input-xlarge" autocomplete="off">
</div>
<div class="span2">
<label>Telephone </label>
<input type="text" name="Telephone" value="<?php echo htmlentities($row_Recordset_QuoteCustomer['Telephone'], ENT_COMPAT, 'utf-8'); ?>" class="span12">
</div>
<div class="span2">
<label>Email </label>
<input type="text" name="Email " value="<?php echo htmlentities(row_Recordset_QuoteCustomer['Email '], ENT_COMPAT, 'utf-8'); ?>" class="span12">
</div>
.........
.
.
.
.
.
.
<script src="../js/jquery.js"></script>
<script src="../js/bootstrap-transition.js"></script>
<script src="../js/bootstrap-alert.js"></script>
<script src="../js/bootstrap-modal.js"></script>
<script src="../js/bootstrap-dropdown.js"></script>
<script src="../js/bootstrap-scrollspy.js"></script>
<script src="../js/bootstrap-tab.js"></script>
<script src="../js/bootstrap-tooltip.js"></script>
<script src="../js/bootstrap-popover.js"></script>
<script src="../js/bootstrap-button.js"></script>
<script src="../js/bootstrap-typeahead.js"></script>
<script src="../js/SpecWorkPages/getItemsList.js"></script>
<script type="text/javascript">
$(document).ready(function()
{
$('input.typeahead').typeahead({
source: function (query, process)
{
$.ajax(
{
url: 'Customer.php',
type: 'POST',
dataType: 'JSON',
data: 'query=' + query,
success: function(data)
{
console.log(data);
process(data);
}
});
}
});
})
</script>
</body>
</html>
<?php
mysql_free_result($RecordsetQuote);
mysql_free_result($Recordset_QuoteStatus);
mysql_free_result($Recordset_QuoteCustomer);
?>
如果我理解正确，您将返回结果，但无法填充输入字段。虽然我不使用Twitter Bootstrap typeahead，但我使用jQuery的自动完成功能做了一些非常类似的事情。下面的代码是未经测试的，当然你需要自己修改它，但希望能有所帮助。
请参阅此工作jsFiddle演示了解类似内容。
PHP
$array = array();
while ($row = mysql_fetch_assoc($sql)) {
array_push($array,array('ContactName'=>$row['ContactName'],'Telephone'=>$row['Telephone'],'Email'=>$row['Email']));
}
echo json_encode($array);
您可以通过手动输入URL（例如：yoursite/Customer.php？query=SomeContactName）来检查返回的内容
[{"ContactName":"Some Contact","Telephone":"5555555555","Email":"email@whatever.com"},
{"ContactName":"Some Other Contact","Telephone":"5555555555","Email":"anotheremail@whatever.com"}]
HTML/Javascript
<script>
$('input.typeahead').typeahead({
source: function (query, process) {
$.ajax({
url: 'Customer.php',
type: 'POST',
dataType: 'JSON',
// data: 'query=' + query,
data: 'query=' + $('#contactName').val(),
success: function(data)
{
var results = data.map(function(item) {
var someItem = { contactname: item.ContactName, telephone: item.Telephone, email: item.Email };
return JSON.stringify(someItem.contactname);
});
return process(results);
}
});
},
minLength: 1,
updater: function(item) {
// This may need some tweaks as it has not been tested
var obj = JSON.parse(item);
return item;
}
});
</script>
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