我有一个将多个表导出到.sql文件中的脚本作为备份。这个脚本运行得很好，但我也想在服务器上保存一份备份！我可以将其作为记录插入，但我不能像以前那样使用move_uploaded_file方法上传照片。
这是我的脚本：
<?php
//ENTER THE RELEVANT INFO BELOW
//http://stackoverflow.com/a/31531996/1620626
$mysqlUserName = "root";
$mysqlPassword = "xxx";
$mysqlHostName = "localhost";
$DbName = "xxx_db";
$backup_name ="mybackup.sql";
$tables = array("table1","table2");
//or add 5th parameter(array) of specific tables: array("mytable1","mytable2","mytable3") for multiple tables
Export_Database($mysqlHostName,$mysqlUserName,$mysqlPassword,$DbName, $tables=false, $backup_name=false );
function Export_Database($host,$user,$pass,$name, $tables=false, $backup_name=false )
{
$mysqli = new mysqli($host,$user,$pass,$name);
$mysqli->select_db($name);
$mysqli->query("SET NAMES 'utf8'");
$queryTables = $mysqli->query('SHOW TABLES');
while($row = $queryTables->fetch_row())
{
$target_tables[] = $row[0];
}
if($tables !== false)
{
$target_tables = array_intersect( $target_tables, $tables);
}
foreach($target_tables as $table)
{
$result = $mysqli->query('SELECT * FROM '.$table);
$fields_amount = $result->field_count;
$rows_num=$mysqli->affected_rows;
$res = $mysqli->query('SHOW CREATE TABLE '.$table);
$TableMLine = $res->fetch_row();
$content = (!isset($content) ? '' : $content) . "'n'n".$TableMLine[1].";'n'n";
for ($i = 0, $st_counter = 0; $i < $fields_amount; $i++, $st_counter=0)
{
while($row = $result->fetch_row())
{ //when started (and every after 100 command cycle):
if ($st_counter%100 == 0 || $st_counter == 0 )
{
$content .= "'nINSERT INTO ".$table." VALUES";
}
$content .= "'n(";
for($j=0; $j<$fields_amount; $j++)
{
$row[$j] = str_replace("'n","''n", addslashes($row[$j]) );
if (isset($row[$j]))
{
$content .= '"'.$row[$j].'"' ;
}
else
{
$content .= '""';
}
if ($j<($fields_amount-1))
{
$content.= ',';
}
}
$content .=")";
//every after 100 command cycle [or at last line] ....p.s. but should be inserted 1 cycle eariler
if ( (($st_counter+1)%100==0 && $st_counter!=0) || $st_counter+1==$rows_num)
{
$content .= ";";
}
else
{
$content .= ",";
}
$st_counter=$st_counter+1;
}
} $content .="'n'n'n";
}
$backup_name = $backup_name ? $backup_name : $name."_(".date('H-i-s')."_".date('d-m-Y').").sql";
//$backup_name = $backup_name ? $backup_name : $name.".sql";
header('Content-Type: application/octet-stream');
header("Content-Transfer-Encoding: Binary");
header("Content-disposition: attachment; filename='"".$backup_name."'"");
move_uploaded_file($backup_name, 'files/bak/'.$backup_name);
echo $content; exit;
}
?>
因此，我想将导出的文件保存到files/bak中，作为用户下载的.sql文件。
因此，这段代码可以将备份文件下载到您的浏览器，从而下载到客户端机器，备份是安全可靠的！
header('Content-Type: application/octet-stream');
header("Content-Transfer-Encoding: Binary");
header("Content-disposition: attachment; filename='"".$backup_name."'"");
echo $content; exit;
但是move_uploaded_file();通过$_FILES机制与上传文件紧密相连，所以不要使用它。
您所需要做的就是将$content写入一个文件，它可以像一样简单地完成
file_put_contents('files/bak/'.$backup_name, $content);
链接到手动-文件放入内容
因此，脚本尾部的完整代码将是
file_put_contents('files/bak/'.$backup_name, $content);
header('Content-Type: application/octet-stream');
header("Content-Transfer-Encoding: Binary");
header("Content-disposition: attachment; filename='"".$backup_name."'"");
echo $content;
exit;
感谢@RiggsFilly的帮助。我提出了自己的解决方案：
$bakDir='files/bak/';
if (!is_dir($bakDir) or !is_writable($bakDir)) {
// Error if directory doesn't exist or isn't writable.
exit($bakDir." is unwritable");
} elseif (!empty($backup_name)) {
// Error if the file exists and isn't writable.
if(file_put_contents($bakDir.$backup_name, $content)){
echo "<script>alert('Backup successfully');</script>";
}else{
echo "<script>alert('Backup failed');</script>";
}
}