Mysql图片库,包含next和previous


Mysql image gallery with next and previous

我正在制作一个照片库,您可以在其中查看全尺寸图像,我想要它具有下一个和上一个按钮,可以在全尺寸图像中循环。到目前为止,我设法使它工作,但当我删除和重新上传图像。

问题是当我打开图片库时被删除并重新上传,当我点击图片以全尺寸查看时我的下一个按钮消失了,只有上一个按钮可以带你画廊中的最后一张图片,然后出现下一个按钮,它会带你当你点击第一张图像时,它会显示在第一张图像上。

这是我的桌子:

Gallery:id(int)主键auto_increment,name varchar(255)照片:id(int)主键auto_increment,路径varchar(255),gallery_id int

Index.hp:

<?php
$query=mysqli_query($conn,"SELECT*FROM gallery");
while($row=mysqli_fetch_array($query)){
$gallery_name=$row['name'];
$galleryid=$row['id'];
echo "<a href='gallery.php?id=$galleryid'>$gallery_name</a><br>";
}
?>

Gallery.php:

session_start();
<div class="piccontainer">
<?php
if(isset($_GET['id']) and is_numeric($_GET['id'])){
$id=$_GET['id'];
}else{
echo "<script>window.location.href='index.php'</script>";
}
$query=mysqli_query($conn,"SELECT*FROM gallery WHERE id='$id'");
while($row=mysqli_fetch_array($query)){
$gallery_name=$row['name'];
echo "<h2>".$gallery_name."</h2>";
}
$query=mysqli_query($conn,"SELECT*FROM photos WHERE gallery_id='$id'");
echo "<div><a class='nazad' href='index.php'>Back</a></div><br><br>";
while($row=mysqli_fetch_array($query)){
$pic_id=$row['id'];
$path=$row['path'];
$_SESSION['galleryid']=$row['gallery_id'];
echo "<div class='picholder'><a href='photo.php?id=$pic_id'><img src='uploads/$path'   /></a></div>";
}
?>
</div>

Photo.php:

session_start();
<div class="piccontent">
<?php
if(isset($_SESSION['galleryid'])){
$back=$_SESSION['galleryid'];
echo "<div><a class='nazad' href='gallery.php?id=$back'>Back</a></div><br><br>
";
}
?>
<?php
if(isset($_GET['id']) and is_numeric($_GET['id'])){
$id=$_GET['id'];
}else{
echo "<script>window.location.href='index.php'</script>";
} 
?>
<div id="links">
<?php
$prevquery=mysqli_query($conn,"SELECT id FROM photos WHERE id<$id AND gallery_id='$gid'");
while($row=mysqli_fetch_array($prevquery)){
$prev=$row['id'];
}
$nextquery=mysqli_query($conn,"SELECT id FROM photos WHERE id>$id AND gallery_id='$gid'");
while($rw=mysqli_fetch_array($nextquery)){
$next=$rw['id'];
}
$nextbtn=(isset($next))?"<a href='photo.php?id=$next'>Next</a>":"";
$prevbtn=(isset($prev))?"<a href='photo.php?id=$prev'>Prev</a>":"";
echo $prevbtn." ".$nextbtn;
?>
</div>
<?php
$query=mysqli_query($conn,"SELECT*FROM photos WHERE id='$id'");
while($row=mysqli_fetch_array($query)){
$path=$row['path'];

echo "<img src='uploads/$path' />";
}
?>
</div>

p>我想你需要一个ORDER BY和LIMIT 1才能得到一行:
$prevquery=mysqli_query($conn,"SELECT id FROM photos WHERE id<$id AND gallery_id='$gid' ORDER BY id DESC LIMIT 1");

使用ASC ORDER对第二个查询执行类似操作。无论如何,这种语法都很糟糕,而且对SQL注入是开放的。使用事先准备好的声明!我还建议尝试嵌套子查询,其中可以包含上一个和下一个照片ID的查询。