我有这个：
$text = 'This is some text /*Comment 1 */ . Some more text{ This is to let you know that /* this is a comment*/. A comment /*this one is */ can be anything }. So the next thing { This is to let you know that /* this is a comment*/. A comment /*this one is */ can be anything } is another topic. /*Final comment*/';
需要这个：
$text = 'This is some text /*Comment 1 */ . Some more text{ This is to let you know that . A comment can be anything }. So the next thing { This is to let you know that . A comment can be anything } is another topic. /*Final comment*/';
尝试过这个：
$text = preg_replace("/'/'*.*?'*'//", "", $text);
问题是，我所尝试的是删除所有的评论。我只想删除{ }中出现的注释。如何做到这一点？
您可以使用以下正则表达式来标记字符串：
$tokens = preg_split('~(/'*.*?'*/|[{}])~s', $str, -1, PREG_SPLIT_DELIM_CAPTURE);
然后迭代令牌，找到打开的{和其中的注释：
$level = 0;
for ($i=1, $n=count($tokens); $i<$n; $i+=2) { // iterate only the special tokens
$token = &$tokens[$i];
switch ($token) {
case '{':
$level++;
break;
case '}':
if ($level < 1) {
echo 'parse error: unexpected "}"';
break 2;
}
$level--;
break;
default: // since we only have four different tokens, this must be a comment
if ($level > 0) {
unset($tokens[$i]);
}
break;
}
}
if ($level > 0) {
echo 'parse error: expecting "}"';
} else {
$str = implode('', $tokens);
}
这可能是最安全的方法：
<?php
$text = 'This is some text /*Comment 1 */ . Some more text{ This is to let you know that /* this is a comment*/. A comment /*this one is */ can be anything }. So the next thing { This is to let you know that /* this is a comment*/. A comment /*this one is */ can be anything } is another topic. /*Final comment*/';
$text = preg_replace_callback('#'{[^}]+'}#msi', 'remove_comments', $text);
var_dump($text);
function remove_comments($text) {
return preg_replace('#/'*.*?'*/#msi', '', $text[0]);
}
?>
它搜索{}，然后删除其中的注释。这将删除{}中的多个注释。