我有以下"键"数组:(数组1)
Array
(
[0] => first_name
[1] => surname
[2] => position
[3] => age
)
此数组应确定数组2中应存在的键和键/值的顺序。因此,在一个完美的世界里,阵列2看起来是这样的:
Array
(
[0] => Array
(
[first_name] => James
[surname] => Johnstone
[position] => Striker
[age] => 42
)
[1] => Array
(
[first_name] => Al
[surname] => MacLean
[position] => Defender
[age] => 22
)
...
)
我遇到的问题在下面的示例数组中。有时:
a) 数组2中键的顺序与数组1不同
b) 数组1中定义的一些密钥在数组2中不存在,比如
Array
(
[0] => Array
(
[position] => Defender
[first_name] => James
[surname] => McDonald
)
[1] => Array
(
[position] => Striker
[first_name] => Ben
[surname] => Lailey
)
...
)
我想要一些帮助来创建一个PHP函数,它将接受一个"格式错误"的数组2,比如上面的数组,并将其转换为应该的样子:按数组1定义的顺序,并添加任何丢失的键以变得"正确",比如:
Array
(
[0] => Array
(
[first_name] => James
[surname] => McDonald
[position] => Defender
[age] =>
)
[1] => Array
(
[first_name] => Ben
[surname] => Lailey
[position] => Striker
[age] =>
)
...
)
本例中使用的密钥是任意的,数组1中可能添加、删除或重新排序了一个新密钥,我需要数组2来尊重数组1。
提前谢谢。
一个简单的实现:
// Pass in an array of keys, and an array of arrays
function cleanArray($keys, $arrays)
{
// Create an empty container for our final output
$final = array();
// Loop through array of arrays
foreach($arrays as $a)
{
// Create empty value for current item
$next = array();
// Loop through keys, in order
foreach($keys as $k)
{
// Assign next key and value if we have it, or a blank string if we don't
$next[$k] = isset($a[k]) ? $a[k] : '';
}
// Add current item to output
$final[] = $next;
}
// Return final values, each item now having its keys ordered and normalized
return $final;
}
尝试使用数组键exists函数http://php.net/manual/en/function.array-key-exists.php
如果不存在,则添加一个缺少键的空元素。(您不关心关联数组中的顺序)
$new=array();
foreach ($array2 as $a2){
foreach($array1 as $k1=>$a1){
$new[][$k1]=$a2[$k1];
}
}