php中的preg替换有问题。
我需要获得以参数结尾的文件扩展名,如:
../font/fontawesome-webfont.eot?v=3.2.1
../font/fontawesome-webfont.eot?#iefix&v=3.2.1
../font/fontawesome-webfont.woff?v=3.2.1
../font/fontawesome-webfont.ttf?v=3.2.1
../font/fontawesome-webfont.svg#fontawesomeregular?v=3.2.1
等等。。。
我试着使用这个功能:
pathinfo($path[1], PATHINFO_EXTENSION);
但它给出了点字符后的最后一个部分,即"1"
我尝试获取css文件,并将url中的路径替换为特定的路径名,以便扩展。。。
这是我的代码示例:
class class_name {
private $img_exts, $font_exts;
function __construct() {
$this->img_exts = array('jpg','jpeg','png','gif');
$this->font_exts = array('ttf','woff','eot','otf');
}
function get_css_file() {
$css = file_get_contents('font-awesome.css');
$css = preg_replace_callback('/url'((?!data)"?''?(.*?)"?''?')/',array($this,'replace_files_callback'), $file);
return $css;
}
function replace_file_callback($file) {
$ext = pathinfo($path[1], PATHINFO_EXTENSION);
// here is the code which i failed!!!
$ext_niddle = preg_replace('/(.*)?('.)?(.*)?'.([a-zA-z0-9]{2,4})'??'#?(.*)?/','$4',$path[1]);
$fname = basename($path[1]);
if (in_array($ext_niddle, $this->img_exts)) {
return "url('../img/$fname')";
} elseif (in_array($ext_niddle, $this->font_exts)) {
return "url('../fonts/$fname')";
} else {
return "url('../data/$fname')";
}
}
}
所以我失败了!
我尝试替换这个:
@font-face {
font-family: 'FontAwesome';
src: url('../font/fontawesome-webfont.eot?v=3.2.1');
src: url('../font/fontawesome-webfont.eot?#iefix&v=3.2.1') format('embedded-opentype'), url('../font/fontawesome-webfont.woff?v=3.2.1') format('woff'), url('../font/fontawesome-webfont.ttf?v=3.2.1') format('truetype'), url('../font/fontawesome-webfont.svg#fontawesomeregular?v=3.2.1') format('svg');
font-weight: normal;
font-style: normal;
}
到此:
@font-face {
font-family: 'FontAwesome';
src: url('../fonts/fontawesome-webfont.eot?v=3.2.1');
src: url('../fonts/fontawesome-webfont.eot?#iefix&v=3.2.1') format('embedded-opentype'), url('../fonts/fontawesome-webfont.woff?v=3.2.1') format('woff'), url('../fonts/fontawesome-webfont.ttf?v=3.2.1') format('truetype'), url('../data/fontawesome-webfont.svg#fontawesomeregular?v=3.2.1') format('svg');
font-weight: normal;
font-style: normal;
}
我对以下文件名感到好奇:../folder/font.name.ttf?ver=1.2.3或者类似的东西。。。
如果你发现一个不合适的代码,请帮帮我!
我将在这个项目中使用它:http://jslibgen.com/
提前感谢。。。
<?php
$uri = "../font/fontawesome-webfont.eot?v=3.2.1";
preg_match("/'/(.+?)'.(.+?)(#|'?)/", $uri, $m);
$ext = $m[2];
echo $ext;
?>
使用parse_url:怎么样
$data = array(
'../font/fontawesome-webfont.eot?v=3.2.1',
'../font/fontawesome-webfont.eot?#iefix&v=3.2.1',
'../font/fontawesome-webfont.woff?v=3.2.1',
'../font/fontawesome-webfont.ttf?v=3.2.1',
'../font/fontawesome-webfont.svg#fontawesomeregular?v=3.2.1',
);
foreach ($data as $url) {
$parse = parse_url($url);
$fname = basename($parse['path']);
$ext = pathinfo($fname, PATHINFO_EXTENSION);
echo "fname=$fname'text=$ext'n";
}
输出:
fname=fontawesome-webfont.eot ext=eot
fname=fontawesome-webfont.eot ext=eot
fname=fontawesome-webfont.woff ext=woff
fname=fontawesome-webfont.ttf ext=ttf
fname=fontawesome-webfont.svg ext=svg