PHP检查用户是否使用函数登录


PHP Check if user is logged in with a function

我在一个网站上工作,索引页面检查用户是否使用以下代码登录:

if (!$_SESSION['login'] && $_SESSION['login'] == "") {
include_once($_SERVER['DOCUMENT_ROOT'] . "/login/");
} elseif ($_SESSION['login'] == 1) {
include_once($_SERVER['DOCUMENT_ROOT'] . "/main/");
}

但我想让它看起来更干净,然后我开始怀疑是否有可能通过功能实现这样的功能

checklogin($_SESSION['login']);

我对函数没有太多经验,所以如果我的问题看起来很愚蠢,我很抱歉,所以提前谢谢。

试试这个

if(check_login()) {
  echo 'You are in!';
} else {
    header('Location: login.php');
    exit;
}
function check_login () {
    if(isset($_SESSION['login'] && $_SESSION['login'] != '') {
       return true;
    } else {
       false;
    }
}

只需使用empty:

if ( empty($_SESSION['login']) ) {
    include_once($_SERVER['DOCUMENT_ROOT'] . "/login/");
} else {
    include_once($_SERVER['DOCUMENT_ROOT'] . "/main/");
}

或者浓缩:

include_once $_SERVER['DOCUMENT_ROOT'].(empty($_SESSION['login']) ? "/login/" : "/main/");

您需要的是:

function userCheck()
{
    return (isSet($_SESSION['login']) && $_SESSION['login']);
}
if(userCheck())
    include_once($_SERVER['DOCUMENT_ROOT'] . "/main/");
else
    include_once($_SERVER['DOCUMENT_ROOT'] . "/login/");

忽略你的方法是否合理的事实,我认为这会达到你的预期:

function checklogin($login){
      if (!$login && $login == "") {
          include_once($_SERVER['DOCUMENT_ROOT'] . "/path/");
      }
}

// **** call to the function
       checklogin($_SESSION['login']);  
// ****

您可以使用此函数:

function checklogin() {
  return (isset($_SESSION['login'])) ? true : false;
}

然后在你想检查用户是否登录的页面上,你可以:

if(checklogin() === true){
  //here you would put what you want to do if the user is logged in
} else {
  //this would be executed if user isn't logged in
  header('Location: protected.php');
  exit();
  //the above would redirect the user
}