我需要你的帮助。我有一个变量名$thetextstring,其中包含9个单词,用换行符和空格分隔,这些单词是我从html表单中提取的。
$thetextstring = "alpha bravo charlie
delta echo
foxtrot
golf hotel india" ;
如何标记php字符串$thetextstring以删除行和空格,并将9个字放入像这样的数组中
$thetextarray[0] = "alpha";
$thetextarray[1] = "bravo";
$thetextarray[2] = "charlie";
$thetextarray[3] = "delta";
$thetextarray[4] = "echo";
$thetextarray[5] = "foxtrot";
$thetextarray[6] = "golf";
$thetextarray[7] = "hotel";
$thetextarray[8] = "india";
我需要php代码来处理这个问题。提前非常感谢!
使用简单explode()函数
$str="new sample string";
$str=preg_replace("/'s+/", " ", $str);
$arr=explode(" ",$str);
print_r($arr);
输出:
Array ( [0] => new [1] => sample [2] => string )
这是您想要的,我删除了所有额外的新行和空格。
$thetextstring = "alpha bravo charlie
delta echo
foxtrot
golf hotel india" ;
$thetextstring = preg_replace("#['s]+#", " ", $thetextstring);
$words = explode(" ", $thetextstring);
print_r($words);
(
[0] => alpha
[1] => bravo
[2] => charlie
[3] => delta
[4] => echo
[5] => foxtrot
[6] => golf
[7] => hotel
[8] => india
)
请参阅PHP explode()
文档注释中的函数multiexplode
,了解如何使用带有多个分隔符的爆炸。
http://php.net/manual/en/function.explode.php#111307
$thetextstring = "alpha bravo charlie delta echo foxtrot golf hotel india" ;
$c= explode(" ", $thetextstring);
print_r($c);
$thetextstring = "alpha bravo charlie
delta echo
foxtrot
golf hotel india" ;
$string = trim(preg_replace('/'s+/', ' ', $thetextstring));
$result = explode(" ", $thetextstring);
print_r( $result );
首先,你应该从给定的字符串中删除所有新行,这样你就可以清楚地看到,你只有一行没有换行符/换行符的字符串。
然后,Explode函数将从由SPACE分隔的给定字符串中创建一个数组。
最后,您可以打印结果,将每个单词看作数组中的单个实体。