我有一个可读的时间字符串，它是这样的，我想把它作为$day,$hours,$minutes,$seconds 3天3小时3分47秒来分隔变量
这是我迄今为止写的代码
<?php
$all_time_string="test 100 years 40 nummonths 60 days 1000 hours 3 minutes 57.9 seconds";
$get_years=explode("years", $all_time_string,2);
if($get_years[1]!=null) {
$get_nomonths=explode("nummonths",$get_years[1],2);
} else {
$get_nomonths=explode("nummonths",$get_years[0],2);
}
if($get_nomonths[1]!=null) {
$no_of_days=explode("days", $get_nomonths[1],2);
} else {
$no_of_days=explode("days", $get_nomonths[0],2);
}
if($no_of_days[1]!=null) {
$get_hours=explode("hours", $no_of_days[1],2);
} else {
$get_hours=explode("hours", $no_of_days[0],2);
}
if($get_hours[1]!=null) {
$get_minutes=explode("minutes", $get_hours[1],2);
} else {
$get_minutes=explode("minutes", $get_hours[0],2);
}
if($get_minutes[1]!=null) {
$get_seconds=explode("seconds", $get_minutes[1],2);
} else {
$get_seconds=explode("seconds", $get_minutes[0],2);
}
echo $get_years[0];
echo $get_nomonths[0];
echo $no_of_days[0];
echo $get_hours[0];
echo $get_minutes[0];
echo $get_seconds[0];
echo "<br>";
?>
您可以使用正则表达式来拆分字符串：
$pattern = "([0-9]+)('s+)years('s+)([0-9]+)('s+)nummonths('s+)([0-9]+)('s+)days('s+)([0-9]+)('s+)hours('s+)([0-9]+)('s+)minutes('s+)([0-9'.]+)('s+)seconds";
$all_time_string="test 100 years 40 nummonths 60 days 1000 hours 3 minutes 57.9 seconds";
$matches = array();
preg_match("/".$pattern."/i", $all_time_string, $matches);
$myArray = array(
"years" => $matches[1],
"months" => $matches[4],
"days" => $matches[7],
"hours" => $matches[10],
"minutes" => $matches[13],
"seconds" => $matches[16],
);
var_dump($myArray);
然后输出为：
array
'years' => string '100' (length=3)
'months' => string '40' (length=2)
'days' => string '60' (length=2)
'hours' => string '1000' (length=4)
'minutes' => string '3' (length=1)
'seconds' => string '57.9' (length=4)