如何从这个字符串中删除"hand#X"
$text = "
Hand #1
text Hand #146822299460:
Hand #2
text Hand #146822236378:
Hand #3
text Hand #346822217642:
Hand #10";
字符串必须变成这样:
text Hand #146822299460:
text Hand #146822236378:
text Hand #346822217642:
我写这篇文章是因为stackoverflow说它包含了很多代码
这应该有效:
$text = "
Hand #1
text Hand #146822299460:
Hand #2
text Hand #146822236378:
Hand #3
text Hand #346822217642:
Hand #10";
echo preg_replace('/^Hand'h+#'d+'s*$/m', '', $text);
输出:
text手牌编号146822299460:
text手牌编号146822236378:
text手号34682217642:
PHP演示:https://eval.in/501402
Regex101演示:https://regex101.com/r/dS7rW7/1
使用preg_replace
echo preg_replace("/^(Hand's#'d+)/", "", $text);
输出:
text :
text :
text :
假设您只想删除字符串开头"hand#X"的行,则使用
echo preg_replace("/^(Hand's#'d+)/m", "", $text);