我正在运行一个脚本，该脚本从MySQL表中获取一行，然后将该行中的某些变量传递到下一页，以便在允许用户更新的表单中使用。
以下是试图将变量传递到下一页的脚本摘录：
if ($row['home_score'] == '0' && $row['away_score'] == '0') {
echo '<td><a href="report_score.html?league=test_league&game_id=" . $row['game_id']"><img src="images/report_icon.png" alt="Report Score" /></a></td>';
}
如果我省略了href中"&game_id="之后的所有内容，则显示良好。然而，一旦我开始添加变量，它就会切断函数并停止显示页面。
我是不是在语法上犯了一些简单的错误？我试过用不同的方式写它，但都无济于事。我需要使用http_build_query（）来实现这一点吗？
如果你需要更多信息，下面是整个脚本代码：
<?php
// Connect to the database:
require ('../mysqli_connect.php');
// Make the query for games from the schedule database and determine the game location:
$q = "SELECT tl.game_date, tl.game_time, tl.away_team, tl.home_team, tl.home_score,tl.away_score, tl.arbiter_id, us.football_location, us.football_map
FROM test_league tl
INNER JOIN user_schools us ON (tl.home_team = us.school_name)
ORDER BY tl.game_id";
$r = mysqli_query($db, $q);
// Declare two variables to help determine the background color of each row:
$i = 0;
$bgcolor = array('row1', 'row2');
// Begin function to print each game as a row:
while ($row = mysqli_fetch_array($r, MYSQLI_ASSOC)) {
echo '<tr class="' . $bgcolor[$i++ % 2] .'"><td>' . $row['game_date'] . '</td><td>' . $row['game_time'] . '</td><td class="alignleft"><a href="">' . $row['away_team'] . '</a> vs<br><a href="">' . $row['home_team'] . '</a></td>';
// Determine if the score has been reported:
if ($row['home_score'] == '0' && $row['away_score'] == '0') {
echo '<td><a href="report_score.html?league=test_league&game_id=" . $row['game_id']"><img src="images/report_icon.png" alt="Report Score" /></a></td>';
} else {
echo '<td>' . $row['home_score'] . '<br>' . $row['away_score'] . '</td>';
}
echo '<td><a href="' . $row['football_map'] . '" target="_blank">' . $row['football_location'] . '</a></td><td><a href="">' . $row['arbiter_id'] . '</a></td></tr>';
}
mysqli_free_result ($r);
mysqli_close($db);
?>
非常感谢您的任何建议！
试试这个，你的语音标记和点混淆了：）
if ($row['home_score'] == '0' && $row['away_score'] == '0') {
echo '<td><a href="report_score.html?league=test_league&game_id=' .$row['game_id']. '"><img src="images/report_icon.png" alt="Report Score" /></a></td>';
}
希望这能有所帮助！
$url = 'www.example.com?' . http_build_query($row,'','&');