*已编辑的格式
我在网上找到了日历的PHP代码，并正在尝试创建一个点击事件，该事件将用户选择的日期设置为变量（稍后将在数据库查询中使用）。
到目前为止，我只想隔离特定日期并将其作为值返回，但到目前为止只能让它返回整个数组（1 2 3 4、5 等）。有没有办法传递所选日期的特定 $list_day 值？
有问题的特定循环：
for($list_day = 1; $list_day <= $days_in_month; $list_day++):
$calendar.= '<td class="calendar-day">';
/* add in the day number */
$calendar.= '<div class="day-number">'.$list_day.'</div>';
完整程序代码：
<!DOCTYPE html>
<html>
<head>
<script src="http://ajax.googleapis.com/ajax/libs/jquery/1.11.1/jquery.min.js"></script>
<script>
$(document).ready(function(){
$("div").click(function(){
alert($('.calendar-day').text());
});
});
</script>
<style>
table.calendar { border-left:1px solid #999; }
tr.calendar-row { }
td.calendar-day { min-height:80px; font-size:11px; position:relative; } * html div.calendar-day { height:80px; }
td.calendar-day-np { background:#eee; min-height:80px; } * html div.calendar-day-np { height:80px; }
td.calendar-day-head { background:#ccc; font-weight:bold; text-align:center; width:35px; padding:5px; border-bottom:1px solid #999; border-top:1px solid #999; border-right:1px solid #999; }
div.day-number:hover { background:#eceff5; }
div.day-number { background:#ffffff; padding:5px; color:#999; font-size:20px; font-weight:bold; float:right; margin:-5px -5px -5px -5px; width:40px; text-align:center; }
/* shared */
td.calendar-day, td.calendar-day-np { width:35px; padding:5px; border-bottom:1px solid #999; border-right:1px solid #999; }
</style>
</head>
</html>
<?php
/* draws a calendar */
function draw_calendar($month,$year){
/* draw table */
$calendar = '<table cellpadding="0" cellspacing="0" class="calendar">';
/* table headings */
$headings = array('Su','M','T','W','Th','F','Sa');
$calendar.= '<tr class="calendar-row"><td class="calendar-day-head">'.implode('</td><td class="calendar-day-head">',$headings).'</td></tr>';
/* days and weeks vars now ... */
$running_day = date('w',mktime(0,0,0,$month,1,$year));
$days_in_month = date('t',mktime(0,0,0,$month,1,$year));
$days_in_this_week = 1;
$day_counter = 0;
$dates_array = array();
/* row for week one */
$calendar.= '<tr class="calendar-row">';
/* print "blank" days until the first of the current week */
for($x = 0; $x < $running_day; $x++):
$calendar.= '<td class="calendar-day-np"></td>';
$days_in_this_week++;
endfor;
/* keep going with days.... */
for($list_day = 1; $list_day <= $days_in_month; $list_day++):
$calendar.= '<td class="calendar-day">';
/* add in the day number */
$calendar.= '<div class="day-number">'.$list_day.'</div>';
/** QUERY THE DATABASE FOR AN ENTRY FOR THIS DAY !! IF MATCHES FOUND, PRINT THEM !! **/
$calendar.= str_repeat('<p> </p>',2);
$calendar.= '</td>';
if($running_day == 6):
$calendar.= '</tr>';
if(($day_counter+1) != $days_in_month):
$calendar.= '<tr class="calendar-row">';
endif;
$running_day = -1;
$days_in_this_week = 0;
endif;
$days_in_this_week++; $running_day++; $day_counter++;
endfor;
/* finish the rest of the days in the week */
if($days_in_this_week < 8):
for($x = 1; $x <= (8 - $days_in_this_week); $x++):
$calendar.= '<div><td class="calendar-day-np"> </td></div>';
endfor;
endif;
/* final row */
$calendar.= '</tr>';
/* end the table */
$calendar.= '</table>';
/* all done, return result */
return $calendar;
}
/* sample usages */
echo '<h2>November 2014</h2>';
echo draw_calendar(11,2014);
echo date('t',mktime(0,0,0,$month,1,$year));
?>
您的问题与您当天使用的 jquery 选择器有关。
取而代之的是，它返回具有该类名的所有div 元素：
$('.calendar-day').text()
使用这个（字面意思）：
$(this).text()
这将仅返回您单击的特定div 的文本。