jQuery@mention使输出成为链接

嘿伙计们，我正在使用霍基的这个插件。它就像推特，你可以@mention某人。我的输出有问题。此方法：

updateHidden: function() {
        var trigger = this.options.trigger;
        var contents = this.element.val();
        for(var key in this.id_map) {
            var regex = trigger+key;
            regex = regex.replace(/[!@#'$%'^&'*'(')'+=-'[']''';,'.'/'{'}'|":<>'?~_]/g, '''$&');
            regex = new RegExp(regex, "g");
            //contents = contents.replace(regex, trigger+'['+this.id_map[key]+']');
            //I changed the code above to:
            contents = contents.replace(regex, '@[' + this.id_map[key] +':' + key + ']');
        }
        $(this.options.hidden).val(contents);
    }

上面的代码将被输出到一个隐藏的标签，影响其值，其中

123：peterwateber]//格式为 @[]。

我使用 PHP 作为我的后端。 我的问题是我想将输出转换为

<a href="www.something.com/profile?pid=123">peterwateber</a>

我对这里的代码有很大的问题，因为我不擅长正则表达式。我想出了代码：

    //THIS CODE SHOULD GET 1234,peterwateber,88,hi.
    $string = "@[1231:peterwateber] sdfsdfsdfsdfsdfsdf@[88:hi]sddsf";
    preg_match_all("^'[(.*?)']^",$string,$matches,PREG_PATTERN_ORDER);
    foreach ($matches[1] as $match) {
        echo $match.'<br/>'; //outputs 1231:peterwateber, 88:hi
    }
    preg_match_all("^'[(['w'd]+):(.*?)']^",$string,$aw,PREG_PATTERN_ORDER);
    foreach ($aw[1] as $match) {
        echo $match.'<br/>'; //sad to say this code outputs the text '1231 and 88'
    }

此外，为了能够获得输出，我有以下表格：

<form class="form-horizontal" data-post="request" method="post">
  <div class="control-group boxTextAreaHolder">
    <textarea placeholder="What are you thinking?" class="UITextarea" title="What are you thinking?" name="statuspost" id="statuspost" tag-status="this"></textarea>
    <input type="hidden" name="tags" id="tag-post" />
  </div>
</form>

提交后，输出将处理到此函数。此函数不允许任何 htmlspecialchars 并检测类似 "http://stackoverflow.com"

private static function validate_text($text = '') {
    // This method is used internally as a FILTER_CALLBACK
    if (mb_strlen($text, 'utf8') < 1)
        return false;
    // Encode all html special characters (<, >, ", & .. etc) and convert
    //$str = nl2br(htmlspecialchars($text));
    $str = htmlspecialchars($text);
    // the new line characters to <br> tags:
    // Remove the new line characters that are left
    $str = str_replace(array(chr(10), chr(13)), '', $str);
    $text = preg_replace('#(script|about|applet|activex|chrome):#is', "''1:", $str);
    $ret = ' ' . $text;
    $ret = preg_replace("#(^|['n ])(['w]+?://['w'#$%&~/.'-;:=,?@'[']+]*)#is", "''1<a href='"''2'" target='"_blank'">''2</a>", $ret);
    $ret = preg_replace("#(^|['n ])((www|ftp)'.['w'#$%&~/.'-;:=,?@'[']+]*)#is", "''1<a href='"http://''2'" target='"_blank'">''2</a>", $ret);
    $ret = preg_replace("#(^|['n ])([a-z0-9&'-_.]+?)@(['w'-]+'.(['w'-'.]+'.)*['w]+)#i", "''1<a href='"mailto:''2@''3'">''2@''3</a>", $ret);
    //$ret = preg_replace("#^*@([)([0-9-])(])#is", "''1<a href='"http://''2'" target='"_blank'">''2</a>", $ret);
    $ret = substr($ret, 1);
    return $ret;
}

现在的问题是我不知道如何将@[1234：peterwateber]转换为**<a href="www.something.com/profile?pid=123">peterwateber</a>**以及如何从htmlspecialchar中排除锚标签