我不知道如何解决PHP错误。
在下面的代码中，我收到错误：
致命错误：无法重新声明getintro（）（之前声明...在第 94 行）
我在下面标记了第 94 行。任何帮助或指导，不胜感激。我的目标是根据数据库的每一行循环出每篇博客文章，只显示部分文本。当它点击链接时，它应该打开完整的博客，并在博客中发表评论.php
<?php // retreive post
include('php/config.php');
include ('php/function.php');
dbConnect();
$blog_query = mysql_query(
'SELECT *
FROM Blog
ORDER BY DATE DESC');
while($row = mysql_fetch_array($blog_query)):
$date = date_create($row['DATE']);
$str = $row['CONTENT'];
$ID = $row['ID'];
LINE 94 function getIntro($str, $count = 200) {
return preg_replace('/'s+?('S+)?$/', '', substr(nl2br($str), 0, $count)) . " <a href='"blog.php?page={$ID}'" class='"changeColor'">Read more...</a>'n";
}
$new_string = getIntro($str);
?>
<div class="post">
<h2><?php echo $row['TITLE']?></h2>
<h3><?php echo date_format($date, 'l, F j, Y')?></h3>
<p><?php echo $new_string?></p>
</div>
</div>
<?php endwhile?>
您的函数是在循环中声明的。将函数声明移出循环。
<?php // retreive post
include('php/config.php');
include ('php/function.php');
dbConnect();
$blog_query = mysql_query(
'SELECT *
FROM Blog
ORDER BY DATE DESC');
function getIntro($str, $count = 200) {
return preg_replace('/'s+?('S+)?$/', '', substr(nl2br($str), 0, $count)) . " <a href='"blog.php?page={$ID}'" class='"changeColor'">Read more...</a>'n";
}
while($row = mysql_fetch_array($blog_query)):
$date = date_create($row['DATE']);
$str = $row['CONTENT'];
$ID = $row['ID'];
$new_string = getIntro($str);
?>
<div class="post">
<h2><?php echo $row['TITLE']?></h2>
<h3><?php echo date_format($date, 'l, F j, Y')?></h3>
<p><?php echo $new_string?></p>
</div>
</div>
<?php endwhile?>
您是在循环中声明一个函数，因此每次迭代它都会重新声明导致问题的相同函数。我会在循环上方声明函数并在循环中调用该函数。
把你的函数声明拿出来 while 循环！（声明必须在您使用之前！
function getIntro($str, $count = 200) {
return preg_replace('/'s+?('S+)?$/', '', substr(nl2br($str), 0, $count)) . " <a href='"blog.php?page={$ID}'" class='"changeColor'">Read more...</a>'n";
}
将函数定义移出循环，例如将其放在 dbConnect 之前：
function getIntro($str, $count = 200) {
return preg_replace('/'s+?('S+)?$/', '', substr(nl2br($str), 0, $count)) . " <a href='"blog.php?page={$ID}'" class='"changeColor'">Read more...</a>'n";
}