使用for/while循环获取数组中所有偶数的平均值 - Getting average of all even numbers in array with for/while loop?

Getting average of all even numbers in array with for/while loop?

我有一个数组，我需要得到数组中所有EVEN数字的平均值，我已经尝试过了，但仍然不起作用。

$aReeks = array(23,245,1,2,12,-10,46,6,66,9999,-55,348,56,6,66,983); 
for ($q = 0; $q < count($aReeks); $q++)
      {
          { 
            if ($aReeks[$q] % 2 == 0)
            $totaaleven = array_sum($aReeks[$q]) / count($aReeks[$q]);
          }
      }
echo $totaaleven

我认为这应该适用于

$aReeks = array(23,245,1,2,12,-10,46,6,66,9999,-55,348,56,6,66,983); 
$evenSum = 0;
$evenCount = 0;
foreach($aReeks as $number) {
    if($number % 2 == 0) {
        $evenSum = $evenSum + $number;
        $evenCount++;
    }
}
$average = $evenSum / $evenCount;

您可以使用array_filter为偶数过滤数组，并简单地将sum除以count，如下所示：

$aReeks = array(23,245,1,2,12,-10,46,6,66,9999,-55,348,56,6,66,983); 
$evenNos = array_filter($aReeks, function($value) {
    return !($value%2);
});
echo array_sum($evenNos)/count($evenNos);