我有这段代码,它清理了用户对名为"用户名"的变量的输入:
$username_clean = preg_replace( "/[^a-zA-Z0-9_]/", "", $_POST['username'] );
if (!strlen($username_clean)){
die("username is blank!");
我想在此页面上的每个输入上执行相同的过程,但由于它是注册表单,我有大约 12 个不同的输入。有没有更简单的方法来清理和检查每个输入,而不是在每个输入上应用 preg_replace() 和 if 语句?
如果你想清理$_POST
中的所有元素,那么你可以创建一个清理函数,并将其应用于所有元素,array_map
:
$post_clean = array_map("sanitization_function", $_POST);
然后,您将通过$post_clean
而不是$_POST
访问变量。
它看起来像:
function sanitize($dirty){
return preg_replace( "/[^a-zA-Z0-9_]/", "", $dirty );
}
$cPOST = array_map("sanitize", $_POST);
if (!strlen($cPOST['username'])){
die("username is blank!");
}
如果您只想清理$_POST
元素的子集,则可以执行以下操作:
$cPOST = array();
$sanitize_keys = array('username','someotherkeytosanitize');
foreach($_POST as $k=>$v)
{
if(in_array($k, $sanitize_keys))
{
$cPOST[$k] = preg_replace( "/[^a-zA-Z0-9_]/", "", $v);
}
else
{
$cPOST[$k] = $v;
}
}
试试这个:
$cPOST = array();
$sanitize_keys = array('username','someotherkeytosanitize');
for($_POST as $k=>$v)
{
if(in_array($k, $sanitize_keys))
{
$cPOST[$k] = preg_replace( "/[^a-zA-Z0-9_]/", "", $v);
if(strlen($cPOST[$k]) == 0){
die("%s is blank", $k);
}
}
else
{
$cPOST[$k] = $v;
}
}
# At this point, the variables in $cPOST are the same as $_POST, unless you
# specified they be sanitized (by including them in the $sanitize_keys array.
# Also, if you get here, you know that the entries $cPOST that correspond
# to the keys in $sanitize_keys were not blank after sanitization.
只需确保将 $sanitize_keys 更改为要清理的任何变量(或 $_POST 键)的数组即可。
如果正则表达式和失败测试相同,则可以编写一个函数:
function validate($input, $input_name) {
$clean_input = preg_replace( "/[^a-zA-Z0-9_]/", "", $input );
if (!strlen($username_clean)){
die("$input_name is blank!");
}
return $clean_input;
}
validate($_POST['username'], "Username");