PHP 中的 foreach 仅通过第一个 JSON 进行迭代 - foreach in php iterates only through the first JSON

请看一下：json的 http://codepad.org/uNlMsvwj。

$json = json_decode($raw_json);
//print_r($json);
$count = count($json->response->results);
$i = 0;
foreach($json->response->results as $item){
  echo($item->entries[$i]->displayname);echo "<br>";
  echo($item->entries[$i]->location->street);echo " "; echo($item->entries[$i]->location->streetnumber);echo "<br>";
  echo($item->entries[$i]->location->zipcode);echo " ";
  echo($item->entries[$i]->location->city);echo "<br>";echo "<br>";
  echo($item->entries[$i]->phonenumbers[0]->area);echo "/"; echo($item->entries[$i]->phonenumbers[0]->number);echo "<br>";
$i++;
}

问题是只打印了第一个 elemet。如果我用 1 手动更改$i，我会得到第二个。

我已经找了3个小时了，找不到解决方案。如果是初学者的错误，请原谅我。

谢谢

更新：谢谢大家的快速帮助

你的意思是像这样迭代结果吗？

foreach($json->response->results as $item) {
  for ($i = 0; $i < count($item->entries); $i++) {
    echo($item->entries[$i]->displayname);echo "<br>";
    echo($item->entries[$i]->location->street);echo " ";
    echo($item->entries[$i]->location->streetnumber);echo "<br>";
    echo($item->entries[$i]->location->zipcode);echo " ";
    echo($item->entries[$i]->location->city);echo "<br>";echo "<br>";
    echo($item->entries[$i]->phonenumbers[0]->area);echo "/"; 
    echo($item->entries[$i]->phonenumbers[0]->number);echo "<br>";
  }
}

此外，您还可以简化echo语句：

foreach($json->response->results as $item) {
  for ($i = 0; $i < count($item->entries); $i++) {
    echo $item->entries[$i]->displayname.'<br>';
    echo $item->entries[$i]->location->street.' ';
    echo $item->entries[$i]->location->streetnumber.'<br>';
    echo $item->entries[$i]->location->zipcode.' ';
    echo $item->entries[$i]->location->city.'<br><br>';
    echo $item->entries[$i]->phonenumbers[0]->area.'/';
    echo $item->entries[$i]->phonenumbers[0]->number.'<br>';
  }
}

试试这个，它有效我测试过它：

foreach($json->response->results[0]->entries as $item){
  echo($item->displayname);echo "<br>";
  echo($item->location->street);echo " ";
  echo($item->location->streetnumber);echo "<br>";
  echo($item->location->zipcode);echo " ";
  echo($item->location->city);echo "<br>";echo "<br>";
  echo($item->phonenumbers[0]->area);echo "/"; echo($item->phonenumbers[0]->number);echo "<br>";
}

你应该像这样回声：

echo $item->entries[$i]->displayname . "<br>";

.连接字符串。此外，echo不使用任何()。

更改

foreach($json->response->results as $item){

自

foreach($json->response->results->entries as $item){

和这些台词

echo($item->entries[$i]->displayname);echo "<br>";

自

echo $item->displayname . "<br>";

因此，您的代码将如下所示：

foreach($json->response->results->entries as $item){
  echo "{$item->displayname}<br />";
  echo "{$item->location->street} {$item->location->streetnumber}<br />";
  echo "{$item->zipcode}<br />";
  echo "{$item->location->city}<br /><br />";
  echo "{$item->phonenumbers[0]->area}/{$item->phonenumbers[0]->number}<br />";
}

尝试 for 循环而不是 foreach：

$json = json_decode($raw_json);
//print_r($json);
$count = count($json->response->results);
foreach($json->response->results->entries as $item){
  echo($item->displayname);echo "<br>";
  echo($item->location->street);echo " ";
  echo($item->location->streetnumber);echo "<br>";
  echo($item->location->zipcode);echo " ";
  echo($item->location->city);echo "<br>";echo "<br>";
  echo($item->phonenumbers[0]->area);echo "/"; echo($item->phonenumbers[0]->number);echo "<br>";
}

。或在 foreach 中包含 for 循环：

$json = json_decode($raw_json);
//print_r($json);
$count = count($json->response->results);
foreach($json->response->results as $item){
  for ($i = 0; $i < count($item->entries); $i++) {
    echo($item->entries[$i]->displayname);echo "<br>";
    echo($item->entries[$i]->location->street);echo " ";
    echo($item->entries[$i]->location->streetnumber);echo "<br>";
    echo($item->entries[$i]->location->zipcode);echo " ";
    echo($item->entries[$i]->location->city);echo "<br>";echo "<br>";
    echo($item->entries[$i]->phonenumbers[0]->area);echo "/";
    echo($item->entries[$i]->phonenumbers[0]->number);echo "<br>";
  }
}