我正在做一个项目，我从 2 天开始堆叠，这是我的问题：我有两个arrays，想检索Array_2中每个对象中的第二个项目，并将其concatenate到PHP中第一个Array_1中每个对象的内容。
Array_1
[[1453274700000,24011],[1453275000000,24222],[1453275300000,24284],[1453275600000,24331],...]
Array_2
[[1453274700000,51951],[1453275000000,52093],[1453275300000,52251],[1453275600000,52288],...]
Wanted_array
[[1453274700000,24011,51951],[1453275000000,24222,52093],[1453275300000,24284,52251],[1453275600000,24331,52288]...]
一个功能性解决方案：
$result = array_map(function (array $a1, array $a2) {
return array_merge($a1, [$a2[1]]);
}, $array_1, $array_2);
这假定所有项目都按顺序排列，并且只需要按其顺序合并，而不是按其第一个值合并。
如果您希望$item[0]定义每个值所属的"组"，则可以循环访问第一个数组并将$item[0]保存为键，$item[1]保存为值。对第二个数组执行相同的操作。现在遍历 array1 的已保存数组，并检查为 array2 保存的数组是否包含相同的键。对 array2 执行相同的操作（如果它有 array1 没有的键），并将其全部保存到新数组中：
<?php
$arr1 = array(
array('1453274700000',24011),
array('1453275000000',24222),
array('1453276000000',24222), // inexistent in $arr2
);
$arr2 = array(
array('1453275000000',52093),
array('1453274700000',51951),
array('1453273000000',24222), // inexistent in $arr1
);
$arr1dictionary = [];
$arr2dictionary = [];
$result = [];
foreach ($arr1 as $collection) {
$arr1dictionary[$collection[0]] = $collection[1];
}
foreach ($arr2 as $collection) {
$arr2dictionary[$collection[0]] = $collection[1];
}
foreach ($arr1dictionary as $key => $value) {
if (isset($arr2dictionary[$key])) {
$result[$key] = [$key, $value, $arr2dictionary[$key]];
} else {
$result[$key] = [$key, $value, null];
}
}
foreach ($arr2dictionary as $key => $value) {
if (isset($result[$key])) {
continue;
}
$result[$key] = [$key, null, $value];
}
$result = array_values($result);
print_r($result);
输出：
Array
(
[0] => Array
(
[0] => 1453274700000
[1] => 24011
[2] => 51951
)
[1] => Array
(
[0] => 1453275000000
[1] => 24222
[2] => 52093
)
[2] => Array
(
[0] => 1453276000000
[1] => 24222
[2] => (null, the value only exists in $arr1)
)
[3] => Array
(
[0] => 1453273000000
[1] => (null, the value only exists in $arr2)
[2] => 24222
)
)
演示
使用array_walk并从$array2中添加第二项（如果存在）。
$array1 = array(
array(1453274700000,24011),
array(1453275000000,24222),
array(1453275300000,24284),
array(1453275600000,24331)
);
$array2 = array(
array(1453274700000,51951),
array(1453275000000,52093),
array(1453275300000,52251),
array(1453275600000,52288),
);
array_walk($array1, function(&$item, $key) use ($array2){
if(isset($array2[$key][1])){
$item[] = $array2[$key][1];
}
});
print_r($array1);
输出
Array
(
[0] => Array
(
[0] => 1453274700000
[1] => 24011
[2] => 51951
)
[1] => Array
(
[0] => 1453275000000
[1] => 24222
[2] => 52093
)
[2] => Array
(
[0] => 1453275300000
[1] => 24284
[2] => 52251
)
[3] => Array
(
[0] => 1453275600000
[1] => 24331
[2] => 52288
)
)
编辑
正如@h2ooooooo指出的那样，数组项可能是随机顺序的。如果数组项可以按随机顺序排列，并且它们与第一个索引值匹配，请使用以下命令（适用于 PHP>= 5.5.0）：
$array1 = array(
array(1453274700000,24011),
array(1453275000000,24222),
array(1453275300000,24284),
array(1453275600000,24331),
array(1453276000000,24222) // no match in $array2
);
$array2 = array(
array(1453275000000,52093),
array(1453274700000,51951),
array(1453275300000,52251),
array(1453275600000,52288),
);
array_walk($array1, function(&$item, $key) use ($array2){
// Find match in $array2
$array2_key = array_search($item[0], array_column($array2, 0));
// If match found
if($array2_key !== false && isset($array2[$array2_key][1])){
$item[] = $array2[$array2_key][1];
}
// No match
else{
$item[] = null;
}
});
print_r($array1);
输出
Array
(
[0] => Array
(
[0] => 1453274700000
[1] => 24011
[2] => 51951
)
[1] => Array
(
[0] => 1453275000000
[1] => 24222
[2] => 52093
)
[2] => Array
(
[0] => 1453275300000
[1] => 24284
[2] => 52251
)
[3] => Array
(
[0] => 1453275600000
[1] => 24331
[2] => 52288
)
[4] => Array
(
[0] => 1453276000000
[1] => 24222
[2] =>
)
)