需要修改日期倒计时的 PHP 代码(当计数达到 0 时希望不显示任何内容） - Need to modify PHP code for date countdown (want to show nothing when count reaches 0)

Need to modify PHP code for date countdown (want to show nothing when count reaches 0)

需要修改日期倒计时的PHP代码（当计数达到0时希望不显示任何内容）

我使用以下代码显示特定日期的文本视觉对象倒计时，分为月、周、天。效果很好。但是，当倒计时达到实际事件日期然后超过事件日期时，它仍然显示绝对差异。我希望代码此时不显示任何内容（没有输出到屏幕）。我将不胜感激有关如何修改此内容的一些指导要执行的代码，如说明所示。

     $d1 = new DateTime();  // now
     $d2 = new DateTime('2014-01-08');  // set the date +1 to compensate for 1-day  
      error in script
     $diff = $d2->diff($d1);
     list($y,$m,$d) = explode('-', $diff->format('%y-%m-%d'));
     $months = $y*12 + $m;
     $weeks = floor($d/7);
     $days = $d%7;
     printf('Countdown To Event - ');
     if ($months) {printf('%d month%s ', $months, $months>1?'s':'');}
     if ($weeks) {printf('%d week%s ', $weeks, $weeks>1?'s':'');}
     if ($days) {printf('%d day%s ', $days, $days>1?'s':'');}

您需要检查差异是正数还是负数。由于 diff 方法返回一个 DateInterval ，因此可以检查 invert 属性。

 $d1 = new DateTime();  // now
 $d2 = new DateTime('2014-01-08');
 $diff = $d2->diff($d1);
 if ($diff->invert == 1) // the countdown is running
 {
     list($y,$m,$d) = explode('-', $diff->format('%y-%m-%d'));
     $months = $y*12 + $m;
     $weeks = floor($d/7);
     $days = $d%7;
     printf('Countdown To Event - ');
     if ($months) {printf('%d month%s ', $months, $months>1?'s':'');}
     if ($weeks) {printf('%d week%s ', $weeks, $weeks>1?'s':'');}
     if ($days) {printf('%d day%s ', $days, $days>1?'s':'');}
 }
 else 
 {
     // The countdown finished, do something!
 }

有很多方法可以做到这一点...

我认为更简单的是：

$FinalDate='2013-09-23';
$d1 = new DateTime();  // now     
$d2 = new DateTime($FinalDate);  // set the date +1 to compensate for 1-day  
$diff = $d2->diff($d1);
list($y,$m,$d) = explode('-', $diff->format('%y-%m-%d'));
$months = $y*12 + $m;
$weeks = floor($d/7);
$days = $d%7;
if(strtotime($FinalDate)>time()){
 printf('Countdown To Event - ');
 if ($months) {printf('%d month%s ', $months, $months>1?'s':'');}
     if ($weeks) {printf('%d week%s ', $weeks, $weeks>1?'s':'');}
     if ($days) {printf('%d day%s ', $days, $days>1?'s':'');}
 }else{
    echo "Actions AFTER the date";
 }

但是这段代码看起来真的很糟糕，你可以做得更好。你可以用javascript来做到这一点，也可以放一个漂亮的秒计数器！

试试这个：

<?php
$d1 = new DateTime();  // now
$d2 = new DateTime('2014-01-08');  // set the date +1 to compensate for 1-day  
$diff = $d2->diff($d1);
list($y,$m,$d) = explode('-', $diff->format('%y-%m-%d'));
if ($d1 < $d2) {
    $months = $y*12 + $m;
    $weeks = floor($d/7);
    $days = $d%7;
    printf('Countdown To Event - ');
    if ($months) {printf('%d month%s ', $months, $months>1?'s':'');}
    if ($weeks) {printf('%d week%s ', $weeks, $weeks>1?'s':'');}
    if ($days) {printf('%d day%s ', $days, $days>1?'s':'');}
}

因此，如果当前日期大于倒计时日期，则根本不做任何操作。