<form action="results.php" name="Search" method="post">
<label>Search by Last Name:</label> <input class="inputbox" type="text" name='lastname'>
<input class="button" type="submit" value="Search" name="lastnamesearch" />
</form><?php
$conn = oci_connect ('TBEETS', '********', 'oradev');
$curs = oci_new_cursor($conn);
$sql = "begin :output :=TBEETS.USER_PKG.SELECT_LAST_NAME(:VAR_LAST_NAME); end;";
$stmt = oci_parse($conn, $sql);
$LAST_NAME="BEETS";
oci_bind_by_name($stmt, ":output", $curs, -1, OCI_B_CURSOR);
oci_bind_by_name($stmt, ":VAR_LAST_NAME", $LAST_NAME);
oci_execute($stmt);
oci_execute($curs);
while ($row = oci_fetch_array($curs, OCI_ASSOC + OCI_RETURN_NULLS)){
$output[] = $row;
}
oci_free_statement($stmt);
oci_free_cursor($curs);
oci_close($conn);
我需要有关结果的帮助.php以显示具有正在搜索的姓氏的行。不确定如何让"姓氏"与变量匹配LAST_NAME
在 results.php 中，您可以使用以下命令检索姓氏：
$lastname = $_POST['lastname'];
要将其显示在一行中，只需将其附加到 HTML 输出中：
...
echo "<tr><td>$lastname</td></tr>";
...
在 results.php 中，您可以使用$_POST方法获取数据
$lname = $_POST['lastname'];
$sql = "select * from tb_name where col_name = '".$lname."' ";
$result = mysql_query($sql);
while($row = mysql_fetch_array$result()) {
$id = $row['col_name'];
//echo your data with
}