我在网站上看到了几个不同的例子,但它并没有从所有 youtube 选项中获取 id......例如,以下链接不适用于下面的正则表达式模式。任何帮助都会很棒。提前致谢:
如果用户转到 youtube 主页并单击他们提供此 URL 的视频之一,它似乎就是这个:http://www.youtube.com/watch?v=hLSoU53DXK8&feature=g-vrec
我的正则表达式将其放入数据库中为:hLSoU53DXK8-vrec,我需要它而不带-vrec。
// YOUTUBE
$youtube = $_POST['youtube'];
function getYoutubeId($youtube) {
$url = parse_url($youtube);
if($url['host'] !== 'youtube.com' &&
$url['host'] !== 'www.youtube.com'&&
$url['host'] !== 'youtu.be'&&
$url['host'] !== 'www.youtu.be')
return false;
$youtube = preg_replace('~
# Match non-linked youtube URL in the wild. (Rev:20111012)
https?:// # Required scheme. Either http or https.
(?:[0-9A-Z-]+'.)? # Optional subdomain.
(?: # Group host alternatives.
youtu'.be/ # Either youtu.be,
| youtube'.com # or youtube.com followed by
'S* # Allow anything up to VIDEO_ID,
[^'w'-'s] # but char before ID is non-ID char.
) # End host alternatives.
(['w'-]{11}) # $1: VIDEO_ID is exactly 11 chars.
(?=[^'w'-]|$) # Assert next char is non-ID or EOS.
(?! # Assert URL is not pre-linked.
[?=&+%'w]* # Allow URL (query) remainder.
(?: # Group pre-linked alternatives.
[''"][^<>]*> # Either inside a start tag,
| </a> # or inside <a> element text contents.
) # End recognized pre-linked alts.
) # End negative lookahead assertion.
[?=&+%'w]* # Consume any URL (query) remainder.
~ix',
'$1',
$youtube);
return $youtube;
}
$youtube_id = getYoutubeId($youtube);
$url = "http://www.youtube.com/watch?v=hLSoU53DXK8&feature=g-vrec";
$query_string = array();
parse_str(parse_url($url, PHP_URL_QUERY), $query_string);
$id = $query_string["v"];
不幸的是,上面的解决方案没有检索短网址"http://youtu.be"的 Youtube ID。因此,基于上面的解决方案,我编写了此函数:
function get_youtube_id( $youtube_url ) {
$url = parse_url($youtube_url);
if( $url['host'] !== 'youtube.com' &&
$url['host'] !== 'www.youtube.com'&&
$url['host'] !== 'youtu.be'&&
$url['host'] !== 'www.youtu.be')
return '';
if( $url['host'] === 'youtube.com' || $url['host'] === 'www.youtube.com' ) :
parse_str(parse_url($youtube_url, PHP_URL_QUERY), $query_string);
return $query_string["v"];
endif;
$youtube_id = substr( $url['path'], 1 );
if( strpos( $youtube_id, '/' ) )
$youtube_id = substr( $youtube_id, 0, strpos( $youtube_id, '/' ) );
return $youtube_id;
}
$youtube = "theURL";
$query_string = array();
parse_str(parse_url($youtube, PHP_URL_QUERY), $query_string);
$youtube_id = $query_string["v"];