几乎像这样：PHP/mySQL - 如何将嵌套行提取到multidimensinal数组中
SELECT products.NAME, products_prices.PRICE FROM products LEFT JOIN products_prices ON products.ID = products_prices.PROD_ID
这通常会导致：
NAME, PRICE
window, 1000
window, 1200
mouse, 1400
因为window有两个价格，可能根本没有价格。我希望它产生一个数组：
$arr = array(
array('NAME' => 'window', 'price' => array(
array('PRICE' => 1000),
array('PRICE' => 1200)
),
array('NAME' => 'mouse', 'price' => array(
array('PRICE' => 1400)
)
);
因此，连接的记录将是子数组。另一个问题可能是多个连接，但只有左连接。如何做好这一点？链接的示例将连接的列放在主部分，我不想这样做。
它看起来像这样：
$dataStore = array();
foreach ($recordSet as $record){
$dataStore[$record['NAME']]['prices'][] = $record['PRICE'];
}
这仅在您确定单个产品名称可以有多个价格时才有效。
//array you get from mysql:
$arrMysql = array(
array('NAME' => 'window', 'PRICE' => 1000),
array('NAME' => 'window', 'PRICE' => 1200),
array('NAME' => 'mouse', 'PRICE' => 1400)
);
$arr = array();
foreach ($arrMysql as $row) {
if (isset($arr[$row['NAME']])) {
if (isset($arr[$row['NAME']]['price'])) {
$arr[$row['NAME']]['price'].push(array('PRICE' => $row['PRICE']));
} else {
$arr[$row['NAME']]['price'] = array(array('PRICE' => $arr[$row['NAME']]['PRICE']), array('PRICE' => $row['PRICE']));
unset($arr[$row['NAME']]['PRICE']);
}
}
else {
$arr[$row['NAME']] = $row;
}
}
//you get:
$arr = array(
'window' => array('NAME' => 'window', 'price' => array(
array('PRICE' => 1000),
array('PRICE' => 1200)
),
'mouse' => array('NAME' => 'mouse', 'price' => array(
array('PRICE' => 1400)
)
);
// and if you want your array:
$arr = array_values($arr);