我有这段代码,它应该连接到php远程文件,并且应该获得表示XML文件的String。但有点不对劲,它给了我错误401。
变量url是php:的方向
String response=getXML("http://ficticiousweb.com/scripts/getMagazinesList.php");
如果我在网络浏览器上粘贴真实的方向(这是一个虚构的方向),它就可以工作,并为我提供XML。
这是我的代码:
public String getXML(String url){
try{
StringBuilder builder = new StringBuilder();
HttpClient httpclient = new DefaultHttpClient();
HttpGet httpget = new HttpGet(url);
HttpResponse response = httpclient.execute(httpget);
int statuscode = response.getStatusLine().getStatusCode();
if(statuscode == 200)
{
HttpEntity entity = response.getEntity();
InputStream content = entity.getContent();
BufferedReader reader = new BufferedReader(new InputStreamReader(content));
String line;
while ((line = reader.readLine()) != null) builder.append(line);
}
else throw new Exception("HTTP error: " + String.valueOf(statuscode));
return builder.toString();
}catch(Exception e){e.printStackTrace();}
return null;
}
代码出了什么问题?
感谢
您需要登录到请求的站点才能下载或访问xml。这可以通过基于所支持内容的身份验证模式来完成。通常,使用的模式有两种类型基本和摘要。下面的代码将帮助您进行BASIC AUTH。
HttpClient httpclient = new DefaultHttpClient();
HttpResponse response;
String _username = "username";
String _password = "password";
try {
((AbstractHttpClient) httpclient).getCredentialsProvider().setCredentials(
new org.apache.http.auth.AuthScope(webhostname, webport)),
new org.apache.http.auth.UsernamePasswordCredentials(_username, _password));
response = httpclient.execute(new HttpGet(completeurlhere));
StatusLine statusLine = response.getStatusLine();
if(statusLine.getStatusCode() == HttpStatus.SC_OK) {
try {
InputStream is = response.getEntity().getContent();
this._data = is;
} catch(Exception ex) {
Log.e("DBF Error",ex.toString());
}
} else {
response.getEntity().getContent().close();
throw new IOException(statusLine.getReasonPhrase());
}
} catch(ClientProtocolException cpe) {
Log.e("ClientProtocolException @ at FPT",cpe.toString());
} catch(Exception ex) {
Log.e("Exception at FETCHPROJECTASK",ex.toString());
}
401表示您无权执行GET请求。您应该询问网站如何验证请求。。。
通过HTTP请求中的Authorization Header进行授权。你应该对此进行调查,并可能用你的证书自己填写标题。。。(如果服务器接受)