我正在尝试通过不同名称的php两次将图像上传到服务器(在mysql表中具有路径(。图像的一个版本为"xxxx.png"，另一个版本的图像为"xxxxt.png"。
我的php是：
<?php
if ($_FILES['photo']) {
$target = "images/properties/";
$target = $target . basename( $_FILES['photo']['name']);
$pic = "images/properties/" .(mysql_real_escape_string($_FILES['photo']['name']));
if (move_uploaded_file($_FILES['photo']['tmp_name'], $target)) {
mysql_query("INSERT INTO `images` (`productcode`, `photo`) VALUES ('$productcode', '$pic' )");
echo "The new image has been added successfully";
} else {
echo "Error uploading new image - please check the format and size";
}
}
?>
上面的代码将图像插入 mysql 数据库并将文件正确上传到服务器。但是，我正在尝试在"缩略图"版本上使用不同的命名约定上传相同的图像两次。我的 html 中的幻灯片脚本仅在文件名末尾以"t"命名时才识别缩略图，因此我的问题。
有人建议我查看 php copy(( 函数来实现这一点，但不清楚如何将这样的函数合并到我现有的代码中。如果需要，很乐意提供html或任何其他信息。
任何帮助非常感谢。我确实有另一个线程试图找出同样的事情，但我不是很清楚！
谢谢京东
如果我正确理解你，你不需要上传这个文件两次。您的服务器上已有此文件。因此，您应该将其复制(可选地执行一些转换以使其更像缩略图(到服务器的硬盘驱动器上并更新数据库。
您的代码应如下所示：
<?php
if($_FILES['photo'])
{
$target_dir = "images/properties/";
$upload_file_name = basename( $_FILES['photo']['name']);
$upload_file_ext = pathinfo($_FILES['photo']['name'], PATHINFO_EXTENSION);
$target_file = $target_dir . $upload_file_name . '.' . $upload_file_ext;
$target_file_sql = $target_dir . mysql_real_escape_string($upload_file_name . '.' . $upload_file_ext);
$target_thumb = $target_dir . $upload_file_name . 't.' . $upload_file_ext;
$target_thumb_sql = $target_dir . mysql_real_escape_string($upload_file_name . 't.' . $upload_file_ext);
if (move_uploaded_file($_FILES['photo']['tmp_name'], $target_file))
{
mysql_query("INSERT INTO `images` (`productcode`, `photo`) VALUES ('$productcode', '$target_file_sql' )");
echo "The new image has been added successfully";
if (copy($target_file, $target_thumb))
{
mysql_query("INSERT INTO `images` (`productcode`, `photo`) VALUES ('$productcode', '$target_thumb_sql' )");
echo "The new thumb image has been added successfully";
} else
{
echo "Error copying thumb file";
}
} else
{
echo "Error uploading new image - please check the format and size";
}
}
同样，这个想法是您不需要连续上传两次文件。您需要做的就是将其复制到服务器上。
正如你被告知的，你应该使用 copy((。我没有完全测试这个，但试一试：
<?php
if ($_FILES['photo'])
{
$target = "images/properties/";
$ext = array_pop(explode('.', $_FILES['photo']['name']));
$copy = $target . basename($_FILES['photo']['name'], '.' . $ext) . 't.' . $ext;
$target = $target . basename($_FILES['photo']['name']);
$pic = "images/properties/" .(mysql_real_escape_string($_FILES['photo']['name']));
if (move_uploaded_file($_FILES['photo']['tmp_name'], $target))
{
copy($target, $copy);
mysql_query("INSERT INTO `images` (`productcode`, `photo`) VALUES ('$productcode', '$pic' )");
echo "The new image has been added successfully";
}
else
{
echo "Error uploading new image - please check the format and size";
}
}
?>