PHP，比较数组并附加差异 - php, compare arrays and append difference

php, compare arrays and append difference

本文关键字：比较数组 PHP | 更新日期: 2023-09-27

我有两个数组：

1：

Array
(
    [0] => stdClass Object
        (
            [id] => 1
            [name] => Type 1
            [rate] => 100.00
        )
    [1] => stdClass Object
        (
            [id] => 2
            [name] => Type 2
            [rate] => 75.00
        )
    [2] => stdClass Object
        (
            [id] => 3
            [name] => Type 3
            [rate] => 50.00
        )
    [3] => stdClass Object
        (
            [id] => 4
            [name] => Type 4
            [rate] => 50.00
        )
)

阿拉伯数字：

Array
(
    [0] => stdClass Object
        (
            [name] => Type 1
            [rate] => 125
        )
    [1] => stdClass Object
        (
            [name] => Type 2
            [rate] => 85
        )
    [2] => stdClass Object
        (
            [name] => Type 3
            [rate] => 65
        )
)

我需要做的是比较两个数组，并将第一个数组中缺少的项目附加到第二个数组。这种情况总是第一个数组比第二个数组有更多的项目。

我尝试使用类似的东西：

$result = array_udiff($array1,$array2,
 function ($obj_a, $obj_b) {
    return $obj_a->name - $obj_b->name;
  }
);

但它只返回一个空数组

这个？

<?php
    $arr1 = array(
        (object)array("id"=>1,"name"=>"type 1","rate"=>100.00),
        (object)array("id"=>2,"name"=>"type 2","rate"=>75.00),
        (object)array("id"=>3,"name"=>"type 3","rate"=>50.00),
        (object)array("id"=>4,"name"=>"type 4","rate"=>50.00)
        );
    $arr2 = array(
        (object)array("name"=>"type 1","rate"=>125),
        (object)array("name"=>"type 2","rate"=>85),
        (object)array("name"=>"type 3","rate"=>65)
        );

    for($i=0;$i<sizeof($arr1);$i++){
        $count=0;
        for($j=0;$j<sizeof($arr2);$j++){
            if($arr1[$i]->name == $arr2[$j]->name){
                $count++;
            }
        }
        if($count==0){
            array_push($arr2,(object)array("name"=>$arr1[$i]->name,"rate"=>$arr1[$i]->rate));
        }
    }
    print_r($arr2);
?>

不需要很复杂，假设你允许数组包含相同类型和结构的对象。我们没有足够的上下文来理解是否有充分的理由你不能。

//$array1 original array
//$array2 target array
$array2 = array_merge($array1, $array2);