如何计算从开始时间和结束时间指定的时间段内每个月包含多少天

这些其他答案似乎并没有回答进一步分解它的最佳方式，而不是两个日期之间的总天数或月数。我试了一下，想出了这个来找到两个日期之间每个月的天数。

我认为步骤是这样的：

1. 计算开始月份的剩余天数(在此示例中四月有 30 天，所以从 4/4 开始意味着 26 天(
2. 计算下个月月初之间的月数和最后一个月(在本例中为 5/1-10/1(5 个月((
3. 循环并计算出整月之间的天数
4. 加上上个月的总天数(6 天(

5. 我认为一个附带要求可能不是你需要的，但会拥有是多年来做到这一点的一种方式。

   $daysInMonths = 数组((; $start = DateTime：：createFromFormat('n/j/y'， '4/4/13'(; $end = DateTime：：createFromFormat('n/j/y'， '10/6/14'(;

   // find days til start of next month
   $daysInMonths[$start->format('Y')][$start->format('n')] = $start->format('t')-$start->format('j');
   // calculate months between start of next month and beginning of last month
   $start->modify('first day of next month');
   $end->modify('first day');
   // returns DateInterval object
   $dateDiff = $start->diff($end);
   //  By multiplying the years by 12 we make sure to account for year spans
   if ($dateDiff->y > 0) {
     $months = $dateDiff->m+(12*$dateDiff->y);
   } else {
     $months = $dateDiff->m;
   }
   // find days in those middle months
   // $start has been advanced to the next month, so we need to log the days in that month
   $daysInMonths[$start->format('Y')][$start->format('n')] = $start->format('t')-$start->format('j');
   $numMonths = $months;
   for ($i = 0;$i<$numMonths;$i++) {
     $start->modify('+1 month');
     $daysInMonths[$start->format('Y')][$start->format('n')] = $start->format('t');
   }
   
   // log the days in the last month
   $daysInMonths[$end->format('Y')][$end->format('n')] = $end->format('j');
   print_r($daysInMonths);
   // Array ( [2013] => Array ( [4] => 26 [5] => 30 [6] => 30 [7] => 31 [8] => 31 [9] => 30 [10] => 7 ) )
   // if you instead did 4/4/13 - 10/6/14 you would get:
   // Array ( [2013] => Array ( [4] => 26 [5] => 30 [6] => 30 [7] => 31 [8] => 31 [9] => 30 [10] => 31 [11] => 30 [12] => 31 ) [2014] => Array ( [1] => 31 [2] => 28 [3] => 31 [4] => 30 [5] => 31 [6] => 30 [7] => 31 [8] => 31 [9] => 30 [10] => 7 ) )