预准备语句上的致命错误 - Fatal error on prepared statement

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我正在编写准备好的语句，但收到以下错误消息：

注意：未定义的索引：用户名在 C：''Program Files (x86(''EasyPHP-12.1''www''inlogg_och_lagar''core.inc.php 在第 34 行

致命错误：

未捕获的异常"PDOException"，消息为"SQLSTATE[42000]"：语法错误或访问冲突：1064 您的 SQL 语法有错误;请查看与您的 MySQL 服务器版本对应的手册，了解在 C：''Program Files (x86(''EasyPHP-12.1''www''inlogg_och_lagar''core.inc.php：34 中第 1 行"附近使用的正确语法堆栈跟踪： #0 C：''Program Files (x86(''EasyPHP-12.1''www''inlogg_och_lagar''core.inc.php(34(： PDOStatement->execute(Array( #1 C：''Program Files (x86(''EasyPHP-12.1''www''inlogg_och_lagar''index.php(23(： getuserrow('username'( #2 {main} 在 C：''Program Files (x86(''EasyPHP-12.1''www''inlogg_och_lagar''core.inc.php 在第 34 行抛出

有人可以告诉我我做错了什么吗？这是一个简单的登录脚本。

这是loginform.inc.php

    <?php 
        if (isset($_POST['username'])&&isset($_POST['password'])) {
        $username = $_POST['username'] ;    
        $password = $_POST['password'] ;
        $password_hash = md5 ($password);   

        if ($username && $password)
        {     
          $query  ="SELECT * FROM USERDATA where `username` = :username AND `password` = :password";
$stmt = $pdo->prepare($query);
$stmt->execute(array(
   ':username' => $_POST['username'],
   ':password' => $password_hash
));
$row = (bool) $stmt->fetch();
            if (!$rows)
            {   
                  echo '<p class="warning">Fel användarnamn/lösenords kombination.</p>';
            } else {    
                $_SESSION['user_id'] = $row;
                header('Location: index.php');
                exit;
            }
        } else {    
              echo '<p class="warning">Du måste fylla i ett användarnamn och lösenord</p>';
            }
    }
    ?>
        <!--- LOGIN FORM --->
        <div id="form-column">
            <p>You need to be loggedin.</p>
            <p>Fill out username and password.</p>
            <form action="<?php echo $current_file; ?>" method="POST"> 
                Användarnamn: <input type="text" name="username"> 
                Lösenord: <input type="password" name="password">
                <input type="submit" value="Log in">
            </form>
        </div>

这是核心.inc.php

    <?php 
    ob_start();
    session_start();
    $current_file = $_SERVER['SCRIPT_NAME'];
    if (isset($_SERVER['HTTP_REFERER'])&&!empty($_SERVER['HTTP_REFERER'])) {
        $http_referer = $_SERVER['HTTP_REFERER'];
    }

    function loggedin () {
        if (isset($_SESSION['user_id'])&&!empty($_SESSION['user_id'])) {
            return true;
        }   else {
            return false;
        }
    }
    function getuserrow ($row) {
    $sql  ="SELECT * FROM USERDATA where id = ?".$_SESSION['user_id']."'";
    global $pdo;
    $stmt = $pdo->prepare($sql);
    $stmt->execute(array($_POST['username']));
    $row = $stmt->fetch();
}
    ?>

这是connect.inc.php

<?php
$dsn = "mysql:host=localhost;dbname=users;charset=utf8";
$opt = array(
    PDO::ATTR_ERRMODE            => PDO::ERRMODE_EXCEPTION,
    PDO::ATTR_DEFAULT_FETCH_MODE => PDO::FETCH_ASSOC
);
$pdo = new PDO($dsn,'root','', $opt);
?>

您的 PDO 对象被定义为 $pdo ，但后来被引用为 $dbh ：

从connect.inc.php ：
```
$pdo = new PDO($dsn,'root','', $opt);
```

从loginform.inc.php ：

global $dbh;
// ...
$stmt = $dbh->prepare($sql);

此外，loginform.inc.php似乎不包括connect.inc.php。

您在 $stmt->execute(array($_POST['username'])) 处缺少第二个参数它应该是

$sql  ="SELECT * FROM USERDATA where username = ? AND password = ?";
$stmt = $pdo->prepare($sql);
$stmt->execute(array($_POST['username'], md5($_POST['password'])));//<== here

替换这个，

global $pdo;  // <- You don't need this one
$sql  ="SELECT * FROM USERDATA where username = ? AND password = ?";
$stmt = $pdo->prepare($sql);
$stmt->execute(array($_POST['username']));
$row = $stmt->fetch();

跟

$query  ="SELECT * FROM USERDATA where `username` = :username AND `password` = :password";
$stmt = $pdo->prepare($query);
$stmt->execute(array(
   ':username' => $_POST['username'],
   ':password' => $password_hash
));
$row = (bool) $stmt->fetch();

为了避免这种情况，您最好坚持使用命名占位符而不是未命名占位符(如?(。