im 编写一个 PHP 简单代码,从文件中读取并从该文件搜索学生学位。 例如,在我的文件中,我有:
123 20
456 18
789 19
例如,我想在警报框中显示"123"度数,其中包含以下代码:
<?php
function show_degree($str) {
echo '<script type="text/javascript">alert("' . $str . '")</script>';
}
$given_number="123";
$myfile = fopen("degree/dm.txt", "r");
while (($line = fgets($myfile)) !== false) {
list($number, $degree) = explode("'t", $line);
if($number==$given_number) {
echo $degree;
show_degree( 'Hello:''n''nYour Degree:''n'.$degree );
}
}
fclose($myfile);
?>
我该怎么办?TNX很多
我用这段代码解决了自己的问题:
<?php
function show_degree($str,$deg) {
$deg=""+$deg;
echo '<script type="text/javascript">alert("' . $str .$deg. '")</script>';
}
$given_number="90222179";
$myfile = fopen("degree/dm.txt", "r");
while (($line = fgets($myfile)) !== false) {
list($number, $degree) = explode("'t", $line);
if($number==$given_number) {
echo $degree;
show_degree( "Hello''n''nYour Degree:''n",$degree );
}
}
fclose($myfile);
?>
尝试使用这个:你的explode("'t", $line);
没有给你所需的结果。
<?php
function show_degree($str)
{
echo '<script type="text/javascript">alert("' . $str . '")</script>';
}
$given_number="123";
$myfile = fopen("degree/dm.txt", "r");
while (($line = fgets($myfile)) !== false)
{
//echo $line;
list($number, $degree) = explode(" ",preg_replace("/'s+/", " ", $line));// change here
if($number==$given_number)
{
// echo $degree;
show_degree( 'Hello:''n''nYour Degree:''n'.$degree );
}
}
fclose($myfile);
?>