PHP 中 JSON obj 的空白页 - Blank Page for JSON Obj in PHP

Blank Page for JSON Obj in PHP

本文关键字：空白 obj JSON PHP | 更新日期: 2023-09-27

当我打印为数组时，没关系，它打印，但它不会打印为JSON Objects，相反，它返回空白页

提前致谢

<?
require_once('include/db_functions.php');
if($_GET){
    $ad = stripslashes($_GET["ad"]);
    try{
        $dbFuncs = new db_functions();
    }catch(PDOException $e){
        print $e -> getMessage();
    }
    $ss = $dbFuncs->getCategoryLista($ad);
    foreach($ss as $ccc){
        $data[] = array(
            "ID" => $ccc['CategoryID'],
            "Name" => $ccc['CategoryName']
        );
    }        
    header("Content-type: application/json; charset=utf-8");
    echo json_encode($data);
}
?>

由于不同的因素，它可能为空，实际上，如果一切按预期正常，您的代码只会输出 JSON。您只编写了快乐的情况，您需要在 json 中包含所有可能的条件：

<?php
header("Content-type: application/json; charset=utf-8");
require_once('include/db_functions.php');
$data = array();
if(isset($_GET["ad"])){
    $ad = stripslashes($_GET["ad"]);
    try{
        $dbFuncs = new db_functions();
        $ss = $dbFuncs->getCategoryLista($ad);
        if(count($ss) != 0){
            $data['success'] = true;
            foreach($ss as $ccc){
                $data['data'][] = array(
                    "ID" => $ccc['CategoryID'],
                    "Name" => $ccc['CategoryName']
                );
            }    
        }else{
            $data['success'] = false;
            $data['data'] = 'count() == 0';
        }
    }catch(PDOException $e){
        print $e -> getMessage();
        $data['success'] = false;
        $data['data'] = 'error = '.$e -> getMessage();
    }
}else{
    $data['success'] = false;
    $data['data'] = '$_GET["ad"] is not set';
}
echo json_encode($data);
?>