PHP:将变量从下拉列表发送到 URL - PHP: Sending Variable from Dropdown to URL

我恳请您提供有关如何通过URL将变量发送到其他PHP站点的意见：

  <form action="deny.php" method="get">
  <div align="left"></div>
  <p><span class="style13" style="height: 23px;">
    <select name="deny" class="style28" style="width: 320px">
      <option value="Select" selected="selected">Select</option>
      <option value="Price">Too expensive</option>
      <option value="Agency">Other Agency</option>
    </select>
    </span></p>
  <p><span class="style13" style="height: 23px;">
  <input type="hidden" name="id" value=<? echo $id; ?> />
  </span> </p>
  <p>
  <? echo '<td><a href="deny.php?submit='.$id.'&deny='.$_GET['deny'].'">Send Feedback</a></td>'; ?>
  </p>
</form>

$id是正确的，但$deny是空

的

我什至尝试过$deny (instead of $_GET['deny']) and $_POST[deny] - 但$deny总是空的。(可在链接中控制(

感谢您的建议！

溴，

斯特凡

用下面的代码替换你的代码：

<script type="text/javascript" src="//ajax.googleapis.com/ajax/libs/jquery/1.9.1/jquery.min.js"></script>
<form action="deny.php" method="get">
  <div align="left"></div>
  <p><span class="style13" style="height: 23px;">
    <select name="deny" class="style28" style="width: 320px">
      <option value="Select" selected="selected">Select</option>
      <option value="Price">Too expensive</option>
      <option value="Agency">Other Agency</option>
    </select>
    </span></p>
  <p><span class="style13" style="height: 23px;">
  <input type="hidden" name="id" value="<?php echo $id; ?>" />
  </span> </p>
  <p>
  <a href="#" id="feedbackLink">Send Feedback</a>
  </p>
</form>
<script type="text/javascript">
    $( document ).ready(function() {
        $('select[name="deny"]').change(function(){
            var link = 'deny.php?submit=<?php echo $id; ?>&deny=';
            $('a#feedbackLink').attr('href', link + $(this).val());
        });
        $('select[name="deny"]').trigger('change');
    });
</script>

如果不提交表单，您不能使用 $_GET、$_POST 等变量。

希望这将解决您的问题。

在

将表单提交到当前脚本之前，不会填充$_GET['deny']。

不要尝试使用 PHP 来构造 URL。让浏览器来做。只需在表单中放置一个提交按钮，并进行适当的输入和操作。这就是形式的用途。

<form action="deny.php" method="get">
  <div align="left"></div>
  <p><span class="style13" style="height: 23px;">
    <select name="deny" class="style28" style="width: 320px">
      <option value="Select" selected="selected">Select</option>
      <option value="Price">Too expensive</option>
      <option value="Agency">Other Agency</option>
    </select>
    </span></p>
  <p><span class="style13" style="height: 23px;">
  </span> </p>
  <p>
  <input type="submit" value="submit">
  </p>
</form>

<form action="deny.php" method="get">
    <div align="left"></div>
    <p>
        <span class="style13" style="height: 23px;">
            <select name="deny" class="style28" style="width: 320px">
                <option value="Select" selected="selected">Select</option>
                <option value="Price">Too expensive</option>
                <option value="Agency">Other Agency</option>
            </select>
        </span>
    </p>
    <p>
         <span class="style13" style="height: 23px;">
              <input type="hidden" name="id" value="<?php echo $id; ?>" /> 
         </span>
    </p>
    <p>
         <input type="submit" value="Send Feedback" value="submit" />
    </p>
</form>
 <?php
      if (isset($_GET)) {
          var_dump($_GET);
      }
 ?>

<form action="/deny.php?id=<? $id ?>" method="get">
<input name="submit" type="submit" value="Feedback" />

做了诀窍：-(

谢谢

斯特凡

试试这个，它已经过测试。

<form action="your_page.php" method="GET"> <!--you may use POST for security as well -->
      <select name="deny">
        <option value="">Select Option</option>
        <option value="Price">Too expensive</option>
        <option value="Agency">Other Agency</option>
      </select>
      <!-- you msut have $id = something -->
      <input type="hidden" name="id" value="<?php echo $id; ?>" /> 
      <input type="submit" value="Send Feedback" value="submit" />
  </form>
 <?php
      echo "<pre>";print_r(($_GET));
 ?>