我有这段代码，我正在尝试将选定的状态放在子猫表中。到目前为止，它返回一个空值。我不确定这是否清楚，但我想要的只是：从选择选项中选择一个状态并提交。我想将选定的状态名称放入我的表子猫中。
enter <?php
include("connect.php");
$state = $row['states']; //Select name
if (isset($_POST[submit])){
$query = "INSERT INTO subcat (sub_name) VALUES ('$state')";
mysql_query($query) or die(mysql_error());
}
?>
<form action="" method="post" name="form">
<?php
$sql = mysql_query("SELECT * FROM state");
echo "<select name='states'>
<option value=''>Select a state</option>";
while ($row = mysql_fetch_assoc($sql)) {
echo "<option value='$row[id]'>$row[name]</option>";
}
echo "</select>";
?>
<input type="submit" name="submit" value="Continue" />
</form> here
谢谢
将$state = $row['states']更改为$state = $_POST['states']
<?php
include("connect.php");
if (isset($_POST[submit]))
{
$state = $_POST['states']; //Select name
$query = "INSERT INTO subcat (sub_name) VALUES ('$state')";
mysql_query($query) or die(mysql_error());
}
?>
<form action="" method="post" name="form">
<?php
$sql = mysql_query("SELECT * FROM state");
echo "<select name='states'>
<option value=''>Select a state</option>";
while ($row = mysql_fetch_assoc($sql)) {
echo "<option value='$row[id]'>$row[name]</option>"; // if you want to
//get the name into table, then use like this
//echo "<option value='$row[name]'>$row[name]</option>"; or
//echo "<option>$row[name]</option>";
}
echo "</select>";
?>
<input type="submit" name="submit" value="Continue" />
</form>
试试这个：
enter <?php
include("connect.php");
if (isset($_POST[submit])){
$state = $_POST['states'];
$query = "INSERT INTO subcat (sub_name) VALUES ('".mysql_real_escape_string($state)."')";
mysql_query($query) or die(mysql_error());
}
?>
<form action="" method="post" name="form">
<?php
$sql = mysql_query("SELECT * FROM state");
echo '<select name="states" id="states">
<option value="">Select a state</option>';
while ($row = mysql_fetch_assoc($sql)) {
echo '<option value="'.$row['name'].'">'.$row['name'].'</option>';
}
echo '</select>';
?>
<input type="submit" name="submit" value="Continue" />
</form> here
不要忘记使用mysql_real_escape_string来防止SQL注入。我已经替换了$state = $row['状态'];$state = $_POST['状态'];
我不知道你从哪里得到$row...
上面会将状态名称插入到数据库中。