如果我使用以下代码：
//Query and connect
$query4 = "SELECT jobno, cdate FROM delivery_comments;"?>
<?php $results4 = sqlsrv_query($connIntranet, $query4);?>
<?php echo $query4;?>
<table>
<?php //Loop through array and display results in table
while ($row4 = sqlsrv_fetch_array($results4)){
$date2 = $row4['cdate'];
$jobno2 = $row4['jobno'];
?>
<tr>
<td><?php echo $jobno2;?>, </td>
<td><?php echo date_format($date2, 'Y-m-d');?></td>
</tr>
<?php } ?>
</table>
我得到这些结果：
87722, 2016-02-16
87704, 2016-02-16
87698, 2016-02-16
92334, 2016-02-16
92447, 2016-02-17
如何编写 WHERE 子句，使其仅返回今天的结果
_____更新_____
我已经尝试了以下所有选项并继续获得：
Warning: sqlsrv_fetch_array() expects parameter 1 to be resource, boolean given in C:'inetpub'wwwroot'portal2'short_delivery'delivery_short4.php on line 22
这是我当前的代码：
<?php
//Query and connect
$query4 = "SELECT jobno, cdate FROM delivery_comments WHERE date(cdate) = CURDATE()" ;
$results4 = sqlsrv_query($connIntranet, $query4);?>
<?php echo $query4;?>
<table>
<?php //Loop through array and display results in table
while ($row4 = sqlsrv_fetch_array($results4)){
$date2 = $row4['cdate'];
$jobno2 = $row4['jobno'];
?>
<tr>
<td><?php echo $jobno2;?>, </td>
<td><?php echo $date2;?></td>
</tr>
<?php } ?>
</table>
我试过：
SELECT jobno, cdate FROM delivery_comments WHERE date(cdate) = CURDATE()
SELECT jobno, date(cdate) FROM delivery_comments where date(cdate) = 'CURDATE()'
SELECT jobno, cdate FROM delivery_comments where DATE_FORMAT(cdate,'%Y-%m-%d')=CURDATE()
这些不会返回错误，但也不会返回结果
SELECT jobno, cdate FROM delivery_comments where cdate = cast(getdate() as date)
SELECT jobno, cdate FROM delivery_comments where cdate = GETDATE()
如果我摆脱了 where 子句，我会收到此错误：
Catchable fatal error: Object of class DateTime could not be converted to string in C:'inetpub'wwwroot'portal2'short_delivery'delivery_short4.php on line 28
如果我在没有 where 子句的情况下重新添加 date_format，它的工作原理是全天显示：
MS SQL Server提供了一个获取当前GETDATE()日期的功能，以便您可以将查询定义为
"SELECT jobno, cdate FROM delivery_comments where cdate = GETDATE();"
> 您可以获取当前日期作为CURDATE()函数。将查询修改为：
"SELECT jobno, cdate FROM delivery_comments where WHERE date(cdate) = CURDATE();"
试试这个查询：
"SELECT jobno, cdate FROM delivery_comments where cdate = cast (GETDATE() as DATE);"
您必须
从cdate中删除时间部分2016-02-17 09:10:56因为 不会等于2016-02-17 。试试这个：
"SELECT jobno, date(cdate) FROM delivery_comments where CONVERT(date,cdate)date() = CONVERT(date,GETDATE()) ;"
像使用它一样
<?php $query4 = "SELECT jobno, CONVERT(date,cdate) as cdate1 FROM delivery_comments where CONVERT(date,cdate) = CONVERT(date,GETDATE()) " ;?>
<?php $results4 = sqlsrv_query($connIntranet, $query4);
if(!$results4)
{
print_r( sqlsrv_errors(), true);
}
?>
<?php echo $query4;?>
<table>
<?php //Loop through array and display results in table
while ($row4 = sqlsrv_fetch_array($results4)){
$date2 = $row4['cdate1'];
$jobno2 = $row4['jobno'];
?>
<tr>
<td><?php echo $jobno2;?>, </td>
<td><?php echo $date2;?></td>
</tr>
<?php } ?>
</table>