如何使用 phpunit 测试字符串

我正在创建这个字符串

'Your maximum heart rate is ' . $int . ' Your body mass index is ' . $float . ' Your body fat percentage is ' . $float '%.'

并返回

我的断言是

$stringFormat = 'Your maximum heart rate is %d. Your body mass index is %f.  Your body fat percentage is %f%.';
        $this->assertStringMatchesFormat($stringFormat, $actualResultm, 'message');

当测试运行时，我收到此错误

FatControllerTest::testBodyInfo
message
Failed asserting that format description matches text.
--- Expected
+++ Actual
@@ @@
-Your maximum heart rate is %d. Your body mass index is %f.  Your body fat percentage is %f%.
+Your maximum heart rate is 193. Your body mass index is 43.181818181818. Your body fat percentage is 6.32302%.

现在我想它一定与我告诉它期望一个无符号的 int 和两个浮点数并且它返回一个长字符串有关，但如果是这种情况，我如何测试像我列出的字符串一样，它将有 3 个区域因大小写而异？ 如果不是这样，那我做错了什么？