我试图创建一个登录页面，但它似乎不起作用。当我输入详细信息并单击登录时。什么也没发生。我尝试再次登录，但仍然没有任何反应。我想发生的是当我登录时会出现一个弹出窗口，我将被定向到主页
<?php
$con = mysqli_connect("localhost","root","","onlineshop");
if (!$con) {
die("Connection failed: " . mysqli_connect_error());
}
?>
<div class = "boxlog1"
<form method="post" action="" enctype="multipart/form-data">
<input type="text" name="uname" placeholder="Username"class="username" required />
<input type="text" name="lpass" placeholder="Password" class="passwordl" required />
<input type="submit" value="Log In" class="log" name="log"/>
</form>
<a href="forget.php"><p class="forget">Forget password</p></a>
</div>
<?php
if (isset($_POST['log'])){
$c_email = $_POST['uname'];
$c_pass = $_POST['lpass'];
$sel_c = "select * from customers where customer_pass='$c_pass' AND customer_email='$c_email'";
$run_c = mysqli_query($con, $sel_c);
$check_customer = mysqli_num_rows($run_c);
if($check_customer == 0){
echo "<script>alert('Password or Email is incorrect!')</script>";
exit();
}
else{
$_SESSION['customer_email']=$c_email;
echo "<script>alert('login!')</script>";
echo "<script>window.open('paymnet.php','_self')</script>";
}
}
?>
将页面添加到表单操作
例如：
<form action"login.php">
或使用
<form action"<?php echo $_SERVER['PHP_SELF']; ?>">
并用" > "关闭您的div 标签，因此
<div class="boxlog1">
工作示例
<?php
if (!isset($_SESSION)) { session_start(); }
$con = mysqli_connect("localhost","root","","onlineshop");
if (!$con) {
die("Connection failed: " . mysqli_connect_error());
}
?>
<div class="boxlog1">
<form method="post" action="<?php echo $_SERVER['PHP_SELF']; ?>" enctype="multipart/form-data">
<input type="text" name="uname" placeholder="Username"class="username" required />
<input type="text" name="lpass" placeholder="Password" class="passwordl" required />
<input type="submit" value="Log In" class="log" name="log"/>
</form>
<a href="forget.php"><p class="forget">Forget password</p></a>
</div>
<?php
if (isset($_POST['log'])){
$c_email = $_POST['uname'];
$c_pass = $_POST['lpass'];
$sel_c = "select * from customers where customer_pass='$c_pass' AND customer_email='$c_email'";
$run_c = mysqli_query($con, $sel_c);
$check_customer = mysqli_num_rows($run_c);
if($check_customer == 0){
echo "<script>alert('Password or Email is incorrect!')</script>";
exit();
} else {
$_SESSION['customer_email']=$c_email;
echo "<script>alert('login!')</script>";
echo "<script>window.open('paymnet.php','_self')</script>";
}
}
?>
这里更新了针对SQL注入的安全性。不要忘记加密您的密码，以免被盗
<?php
if (!isset($_SESSION)) { session_start(); }
$con = mysqli_connect("localhost","root","","onlineshop");
if (!$con) {
die("Connection failed: " . mysqli_connect_error());
}
?>
<div class="boxlog1">
<form method="post" action="<?php echo $_SERVER['PHP_SELF']; ?>" enctype="multipart/form-data">
<input type="text" name="uname" placeholder="Username"class="username" required />
<input type="text" name="lpass" placeholder="Password" class="passwordl" required />
<input type="submit" value="Log In" class="log" name="log"/>
</form>
<a href="forget.php"><p class="forget">Forget password</p></a>
</div>
<?php
if (isset($_POST['log']) && isset($_POST['uname']) && isset($_POST['lpass'])){
$c_email = bin2hex(htmlspecialchars($_POST['uname']));
$c_pass = bin2hex(htmlspecialchars($_POST['lpass']));
$sel_c = "SELECT * FROM customers WHERE customer_pass=UNHEX('$c_pass') AND customer_email=UNHEX('$c_email')";
$run_c = mysqli_query($con, $sel_c);
$check_customer = mysqli_num_rows($run_c);
if($check_customer === 0){
echo "<script>alert('Password or Email is incorrect!')</script>";
exit();
} else {
$_SESSION['customer_email']=$c_email;
echo "<script>alert('login!')</script>";
echo "<script>window.open('paymnet.php','_self')</script>";
}
}
?>
我并没有太大的改变。只需正确关闭您的div 标签并添加操作即可。但是，它确实可以在没有填写操作的情况下工作。