我的文件中有 12 个函数，但显示Call to a member function prepare() on a non-object时出错
这是问题上升
<?php
function getUsers() {//returns an array of users
global $db;
$list = array();
$stmt = $db->prepare('SELECT username FROM user_info');
$users = $stmt->fetch(PDO::FETCH_ASSOC);
if (is_array($users) || is_object($users))
{
foreach ($users as $user) {
array_push($list, $user[0]);
}return $list;
}
}
$users = getUsers();
function getImageURL($user) {
$stmt = $db->prepare('SELECT propic FROM user_info WHERE username=:username');
$stmt->execute(array(':username' => $user));
$source = $stmt->fetch(PDO::FETCH_ASSOC);
return $source;
}
这是我的连接文件代码
ob_start();
session_start();
//set timezone
date_default_timezone_set('Asia/Kolkata');
//database credentials
define('DBHOST','localhost');
define('DBUSER','sanoj');
define('DBPASS','123456');
define('DBNAME','1video');
//application address
define('DIR','http://www.blogtom.com/');
define('SITEEMAIL','sanoj@gmail.com');
try {
//create PDO connection
$db = new PDO("mysql:host=".DBHOST.";port=3306;dbname=".DBNAME, DBUSER, DBPASS);
$db->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION);
} catch(PDOException $e) {
//show error
echo '<p class="bg-danger">'.$e->getMessage().'</p>';
exit;
}
//include the user class, pass in the database connection
include('classes/user.php');
$user = new User($db);
正如我提到的，我的文件中有 12 个功能，有人可以帮助我如何解决这个问题吗
终于解决了
function getUsers() {//returns an array of users
global $db;
$list = array();
$stmt = $db->prepare('SELECT username FROM user_info');
$users = $stmt->fetch(PDO::FETCH_ASSOC);
if (is_array($users) || is_object($users)) {
foreach ($users as $user) {
array_push($list, $user[0]);
}return $list;
}
}
$users = getUsers();
function getImageURL($user) {
global $db;
$stmt = $db->prepare('SELECT propic FROM user_info WHERE username=:username');
$stmt->execute(array(':username' => $user));
$source = $stmt->fetch(PDO::FETCH_ASSOC);
return $source;
}