我有一个jQuery帖子到一个PHP页面,生成一个JSON响应。它成功生成 JSON,因为我让它显示整个响应。但是在 .each 上,我无法让它发出警报。 任何想法都值得赞赏。谢谢。JSON 如下所示:
[{"Part_Field":"Part_Note:3","Part_Value":"ValueofPart"},{"Part_Field":"Ft_In:3","Part_Value":"12"}, ...
j查询:
$.post('/scripts/update_detail.php' , field_id + "=" + value, function(data){
var d = document.getElementById("displayjson");
d.innerHTML = data;
$.each( data, function( key, value ) {
alert( value.Part_Field );
});
});
你最后忘记了字符串},"json");
。
更正后的代码应为:
$.post('/scripts/update_detail.php' , field_id + "=" + value, function(data){
var d = document.getElementById("displayjson");
d.innerHTML = data;
$.each( data, function( key, value ) {
alert( value.Part_Field );
});
},"json"); // Here, you need to tell jQuery that whatever response
// we are getting from server is a JSON string, in your case,
//it was considering it as a string.