<?php
$dir = opendir('C:'Users'Prometheus'Desktop'milkmaid');
$i = 1;
// loop through all the files in the directory
while (false !== ($file = readdir($dir)))
{
if ($file != "." && $file != "..") {
$newName = $i.'.mp4';
$oldname = $file;
rename($oldname, $newName);
$i++;
}
}
?>
当我运行上面的脚本时，我收到以下错误：
系统找不到指定的文件。（代码：2）
$dir不是字符串。您无法$file连接它。您需要将目录放在单独的变量中，并且不要忘记在目录和文件名之间放置一个/。
在
rename()中添加$dir对我有用
<?php
$dir = opendir('C:'Users'Prometheus'Desktop'milkmaid');
$i = 1;
// loop through all the files in the directory
while (false !== ($file = readdir($dir)))
{
if ($file != "." && $file != "..") {
$newName = $i.'.mp4';
$oldname = $file;
rename($dir.$oldname, $dir.$newName);
$i++;
}
}
?>
像这样使用它：-
$directory = '/public_html/testfolder/';
$i=1;
if ($handle = opendir($directory)) {
while (false !== ($fileName = readdir($handle))) {
$newName = $i.'.mp4';
rename($directory . $fileName, $directory . $newName);
$i++:
}
closedir($handle);
}
这对
我有用
<?php
$counter = 1;
$dir = 'D:'files'; //path of folder
if ($handle = opendir($dir))
{
while (false !== ($fileName = readdir($handle)))
{
if($fileName != '.' && $fileName != '..')
{
$newName = $counter . " - " . $fileName;
rename($dir."/".$fileName, $dir."/".$newName);
$counter++;
}
}
closedir($handle);
}
?>