数组和对象之间的PHP类型转换是怎么回事 - What is going on with PHP type conversion between array and object

当我这样做时：

<?php
$object = array(
    'key' => 'value',
    1 => 'value',
    '11' => 'value',
    '22' => 'value'
);
print_r($object); echo'<br>';
$object = (object)$object;
print_r($object); echo'<br>';echo'<br>';
//ok looks good so far but then
echo $object->key       . '<br>'; // good
echo $object->{1}       . '<br>'; // bad 
echo $object->{11}      . '<br>'; // bad
echo $object->{'22'}    . '<br>'; // bad
$object->key = 'changed value';
$object->{1} = 'changed value';
$object->{'11'} = 'changed value';
$object->{'22'} = 'changed value';
echo'<br>'; print_r($object); echo'<br>';echo'<br>';
echo $object->key       . '<br>'; // good
echo $object->{1}       . '<br>'; // good 
echo $object->{11}      . '<br>'; // good
echo $object->{'22'}    . '<br>'; // good
$object = (array)$object;
echo'<br>'; print_r($object);echo'<br>';echo'<br>';
echo $object['key']     . '<br>'; // good
echo $object[1]         . '<br>'; // wtf 
echo $object['11']      . '<br>'; // wtf
echo $object['22']      . '<br>'; // wtf    
?>

结果我得到这个：

Array           ( [key] => value [1] => value [11] => value [22] => value ) 
stdClass Object ( [key] => value [1] => value [11] => value [22] => value ) 
value
Notice: Undefined property: stdClass::$1 in C:'Users'wl'Documents'USBWebserver v8.5'USBWebserver v8.5'8.5'root'Client'test.php on line 19
Notice: Undefined property: stdClass::$11 in C:'Users'wl'Documents'USBWebserver v8.5'USBWebserver v8.5'8.5'root'Client'test.php on line 20
Notice: Undefined property: stdClass::$22 in C:'Users'wl'Documents'USBWebserver v8.5'USBWebserver v8.5'8.5'root'Client'test.php on line 21

stdClass Object ( [key] => changed value [1] => value [11] => value [22] => value [1] => changed value [11] => changed value [22] => changed value ) 
changed value
changed value
changed value
changed value
Array ( [key] => changed value [1] => value [11] => value [22] => value [1] => changed value [11] => changed value [22] => changed value ) 
changed value
value
value
value

这是PHP中的一个错误，为什么会发生这种情况。数组或对象如何具有 2 个具有不同值的相等键！？

更新：

NikiC给了我一个答案，在这里解释：The Symtable

基本上，数组将数字键存储为整数，对象将数字键存储为字符串。但是，当您执行数组到对象或对象到数组强制转换时，不会强制执行该约束。

array (size=7)
  'key' => string 'changed value' (length=13)
  1 => string 'value' (length=5)
  11 => string 'value' (length=5)
  22 => string 'value' (length=5)
  '1' => string 'changed value' (length=13)
  '11' => string 'changed value' (length=13)
  '22' => string 'changed value' (length=13)

这是

不正确的;例如，11是整数，'11'是一个字符串（两个不同的键）。

使用var_dump而不是print_r，因为它显示类型。

我建议你尝试使用这个脚本：

<?php
$object = array(
  'key' => 'value',
  1 => 'value',
  '11' => 'value',
  '22' => 'value'
);
$object = (object) $object;
var_dump($object);
$object->key = 'changed value';
$object->{1} = 'changed value';
$object->{'11'} = 'changed value';
$object->{'22'} = 'changed value';
$object = (array) $object;
var_dump($object);

这里肯定有一些奇怪之处，但你不能指望得到好的结果，因为以整数开头的变量是非法的。