如何解决Laravel 4中的“目标[接口]不可实例化”


How do I solve "Target [Interface] is not instantiable" in Laravel 4?

我的错误消息:

Illuminate ' Container ' BindingResolutionException 
Target [Project'Backend'Service'Validation'ValidableInterface] is not instantiable.
我知道接口

和抽象类是不可实例化的,所以我知道Laravel不应该试图实例化我的接口。然而,不知何故,它正在尝试,我怀疑这可能是一个具有约束力的问题......即使我相信我已经正确绑定了它并将其注册为服务提供商。

我应该提到,我已经从Chris Fidao的"实现Laravel"中取出了这个例子,它几乎是相同的!

这是我的表单类的前几行:

namespace Project'Backend'Service'Form'Job;
use Project'Backend'Service'Validation'ValidableInterface;
use Project'Backend'Repo'Job'JobInterface;
class JobForm {
    /**
     * Form Data
     *
     * @var array
     */
    protected $data;
    /**
     * Validator
     *
     * @var 'Project'Backend'Form'Service'ValidableInterface
     */
    protected $validator;
    /**
     * Job repository
     *
     * @var 'Project'Backend'Repo'Job'JobInterface
     */
    protected $job;
    public function __construct(ValidableInterface $validator, JobInterface $job)
    {
        $this->validator = $validator;
        $this->job = $job;
    }

这是我的验证器类的前几行:

namespace Project'Backend'Service'Form'Job;
use Project'Backend'Service'Validation'AbstractLaravelValidator;
class JobFormValidator extends AbstractLaravelValidator {
    // Includes some validation rules

这是抽象验证器:

namespace Project'Backend'Service'Validation;
use Illuminate'Validation'Factory;
abstract class AbstractLaravelValidator implements ValidableInterface {
    /**
     * Validator
     *
     * @var 'Illuminate'Validation'Factory
     */
    protected $validator;
    /**
     * Validation data key => value array
     *
     * @var Array
     */
    protected $data = array();
    /**
     * Validation errors
     *
     * @var Array
     */
    protected $errors = array();
    /**
     * Validation rules
     *
     * @var Array
     */
    protected $rules = array();
    /**
     * Custom validation messages
     *
     * @var Array
     */
    protected $messages = array();
    public function __construct(Factory $validator)
    {
        $this->validator = $validator;
    }

这是我将其全部绑定到应用程序的代码:

namespace Project'Backend'Service'Validation;
use Illuminate'Support'ServiceProvider;
use Project'Backend'Service'Form'Job'JobFormValidator;
class ValidationServiceProvider extends ServiceProvider {
    public function register()
    {
        $app = $this->app;
        $app->bind('Project'Backend'Service'Form'Job'JobFormValidator', function($app)
        {
            return new JobFormValidator($app['validator']);
        });
    }
}
然后在 app/

config/app.php 中注册:

.....
'Project'Backend'Service'Validation'ValidationServiceProvider',
....

最后,这些是我的控制器的前几行:

use Project'Backend'Repo'Job'JobInterface;
use Project'Backend'Service'Form'Job'JobForm;
class JobController extends 'BaseController {
    protected $jobform;
    function __construct(JobInterface $job, JobForm $jobform)
    {
        $this->job = $job;
        $this->jobform = $jobform;
    }

通过类型提示将其注入构造函数时,您需要告诉 Laravel它应该将哪个实例用于某个接口。

您可以使用 bind() 方法执行此操作(例如,在您的服务提供商中)

$app->bind('JobInterface', 'Job'); // Job being the class you want to be used

我强烈建议你在这里观看视频,其中Laravel的创造者Taylor Otwell解释了这个和其他一些事情。

首先,您需要使用

/

app/Providers/AppServiceProvider.php

<?php namespace App'Providers;
use Illuminate'Support'ServiceProvider;
class AppServiceProvider extends ServiceProvider {
    /**
     * Bootstrap any application services.
     *
     * @return void
     */
    public function boot()
    {
        //
    }
    /**
     * Register any application services.
     *
     * @return void
     */
    public function register()
    {
        //
        $this->app->bind('JobInterface', 'Job');
    }
}

完成此更改后

运行作曲家更新