需要获取 JavaScript 错误对象


getting javascript error object required

我正在获取div标签的偏移宽度。下面是代码。

 <body>
  <div id="marqueeborder" onmouseover="pxptick=0" onmouseout="pxptick=scrollspeed">
<div id="marqueecontent">

<?php
    // Original script by Walter Heitman Jr, first published on http://techblog.shanock.com
    // List your stocks here, separated by commas, no spaces, in the order you want them displayed:
    $stocks = "idt,iye,mill,pwer,spy,f,msft,x,sbux,sne,ge,dow,t";
    // Function to copy a stock quote CSV from Yahoo to the local cache. CSV contains symbol, price, and change
    function upsfile($stock) { copy("http://finance.yahoo.com/d/quotes.csv?s=$stock&f=sl1c1&e=.csv","stockcache/".$stock.".csv"); }
    foreach ( explode(",", $stocks) as $stock ) {
        // Where the stock quote info file should be...
        $local_file = "stockcache/".$stock.".csv";
        // ...if it exists. If not, download it.
        if (!file_exists($local_file)) { upsfile($stock); }
        // Else,If it's out-of-date by 15 mins (900 seconds) or more, update it.
        elseif (filemtime($local_file) <= (time() - 900)) { upsfile($stock); }
        // Open the file, load our values into an array...
        $local_file = fopen ("stockcache/".$stock.".csv","r");
        $stock_info = fgetcsv ($local_file, 1000, ",");
        // ...format, and output them. I made the symbols into links to Yahoo's stock pages.
        echo "<span class='"stockbox'"><a href='"http://finance.yahoo.com/q?s=".$stock_info[0]."'">".$stock_info[0]."</a> ".sprintf("%.2f",$stock_info[1])." <span style='"";
        // Green prices for up, red for down
        if ($stock_info[2]>=0) { echo "color: #009900;'">&uarr;";   }
        elseif ($stock_info[2]<0) { echo "color: #ff0000;'">&darr;"; }
        echo sprintf("%.2f",abs($stock_info[2]))."</span></span>'n";
        // Done!
        fclose($local_file); 
    }
?>
<span class="stockbox" style="font-size:0.6em">Quotes from <a href="http://finance.yahoo.com/">Yahoo Finance</a></span>
</div>
</div>
 </body>

下面是 JavaScript 函数,它将被称为页面的 onlaod。

<script type="text/javascript">
    // Original script by Walter Heitman Jr, first published on http://techblog.shanock.com
    // Set an initial scroll speed. This equates to the number of pixels shifted per tick
    var scrollspeed=2;
    var pxptick=scrollspeed;
    function startmarquee(){
        alert("hi");
        // Make a shortcut referencing our div with the content we want to scroll
        var marqueediv=document.getElementById("marqueecontent");
        alert("marqueediv"+marqueediv);
        alert("hi"+marqueediv.innerHTML);
        // Get the total width of our available scroll area
        var marqueewidth=document.getElementById("marqueeborder").offsetWidth;
        alert("marqueewidth"+marqueewidth);
        // Get the width of the content we want to scroll
        var contentwidth=marqueediv.offsetWidth;
        alert("contentwidth"+contentwidth);
        // Start the ticker at 50 milliseconds per tick, adjust this to suit your preferences
        // Be warned, setting this lower has heavy impact on client-side CPU usage. Be gentle.
        var lefttime=setInterval("scrollmarquee()",50);
        alert("lefttime"+lefttime);
    }
    function scrollmarquee(){
        // Check position of the div, then shift it left by the set amount of pixels.
        if (parseInt(marqueediv.style.left)>(contentwidth*(-1)))
            marqueediv.style.left=parseInt(marqueediv.style.left)-pxptick+"px";
        // If it's at the end, move it back to the right.
        else
            marqueediv.style.left=parseInt(marqueewidth)+"px";
    }
    window.onload=startmarquee();
</script>

当 IAM 在服务器上运行上述代码时,IAM 在第 46 行收到 JavaScript 错误作为"需要对象",也是 alert("marqueediv"+marqueediv); 是"marqueedivnull",在该警报之后,我收到 JavaScript 错误。

我的问题是,div 标签是否未被识别?为什么?所以只有它作为空对象,我该如何解决这个问题?

谢谢。

您立即调用startmarquee并尝试将其返回值(undefined)分配给window.onload

据推测,脚本出现在<head>中,并且在您运行它时div 不存在。

将函数分配给onload,而不是其返回值。

window.onload=startmarquee;

您可以复制脚本并将其放在正文结束标记之前并删除window.onload=startmarquee();从而确保所有元素都已加载并可访问

就像@Quentin说的,当你引用它时,带有 id 的元素可能没有加载到 DOM 中