我想找到所有有 $string_before [ MATCH ] anytext $string_after
的结果PHP代码:
$page = "anything/pages/Reading/120002/anything><div class='test'>";
$string_before = '/pages/Reading/';
$string_after = '/(.*?)><div class';
$regex= "'/".$string_before."([^#]+)".$string_after."'/";
preg_match_all($regex, $page, $matches);
var_dump($matches);
// I should be getting "120002" in the example above
上面的代码不起作用...输出为空任何想法...谢谢
### 修改我现在尝试了这个:
$page = "anything/pages/Reading/120002/anything><div class='test'>";
$delimiter = "#";
$string_before = '/pages/Reading/';
$string_after = '/(.*?)><div class=';
$regex = $delimiter.$string_before."([^#]+)".$string_after.$delimiter;
echo $regex.'<br>';
preg_match_all($pattern, $page, $matches);
var_dump($matches);
我的正则表达式是:
#/pages/Reading/([^#]+)/(.*?)>
所以 $string_After 没有正确输出有问题......
我收到以下 2 个错误:
Notice: Undefined variable: pattern on line 66 (that's the preg_match_all)
Warning: preg_match_all(): Empty regular expression on line 66
NULL
PHP 正则表达式前后都采用分隔符。您已将分隔符设置为 '/
,这将不起作用,因为 1) 它是两个字符,2) 您在$string_before
和$string_after
变量中使用了多个斜杠。
如果您将其更改为其他内容,例如这样,它将起作用,并且您将在$matches[1]
中得到结果:
$regex= "@".$string_before."([^#]+)".$string_after."@";
你只需要转义你的模式(即用''/替换所有/)
$page = "anything/pages/Reading/120002/anything><div class='test'>";
$string_before = ''/pages'/Reading'/';
$string_after = ''/(.*?)><div class';
$regex= "/".$string_before."([^#]+)".$string_after."/";
preg_match_all($regex, $page, $matches);
var_dump($matches);