Android Login with php/mysql 不起作用

我是Android开发的新手，我这里有一些我构建的代码，以便在我的移动应用程序中具有登录功能。我正在尝试将输入文本中输入的数据的值进行比较到 mysql 数据库中，但似乎我不明白重点，我真的不知道我的代码是否引导我进入某事，或者这只是胡说八道，你们能在这里帮我吗？顺便说一句，我没有收到任何错误，只是单击按钮后没有结果。

这是我的代码：

**

protected void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.main);
        // Edit Text
        inputEmail = (EditText) findViewById(R.id.inputEmail);
        inputPassword = (EditText) findViewById(R.id.inputPassword);
        // Create button
        Button btnSubmit = (Button) findViewById(R.id.btnLogin);
        // button click event
        btnSubmit.setOnClickListener(new View.OnClickListener() {
            @Override
            public void onClick(View view) {
                // creating new product in background thread
                new CheckLogin().execute();
            }
        });     
    }
    class CheckLogin extends AsyncTask<String, String, String> {
        /**
         * Before starting background thread Show Progress Dialog
         * */
        @Override
        protected void onPreExecute() {
            super.onPreExecute();
            pDialog = new ProgressDialog(Main.this);
            pDialog.setMessage("Logging in..");
            pDialog.setIndeterminate(false);
            pDialog.setCancelable(true);
            pDialog.show();
        }
        /**
         * Creating product
         * */
        protected String doInBackground(String... args) {
            String eadd = inputEmail.getText().toString();
            String password = inputPassword.getText().toString();
            httpclient = new DefaultHttpClient();
            httppost = new HttpPost("http://10.0.2.2/TheCalling/log_in.php");

            try {
                nameValuePairs = new ArrayList<NameValuePair>();
                nameValuePairs.add(new BasicNameValuePair("eadd", eadd));
                nameValuePairs.add(new BasicNameValuePair("password", password));
                httppost.setEntity(new UrlEncodedFormEntity(nameValuePairs));
                response = httpclient.execute(httppost);
                if(response.getStatusLine().getStatusCode()==200){
                    entity = response.getEntity();
                    if(entity != null){
                        InputStream instream = entity.getContent();
                        JSONObject jsonResponse = new JSONObject(convertStreamToString(instream));
                        String inputEmail = jsonResponse.getString("eadd");
                        String inputPassword = jsonResponse.getString("password");
                        if(eadd.equals(inputEmail) && password.equals(inputPassword)){
                            SharedPreferences sp = getSharedPreferences("logindetails", 0);
                            SharedPreferences.Editor spedit = sp.edit();
                            spedit.putString("eadd", eadd);
                            spedit.putString("password", password);
                            spedit.commit();
                            Toast.makeText(getBaseContext(), "SUCCESS!", Toast.LENGTH_SHORT).show();

                        }else{
                            Toast.makeText(getBaseContext(), "Invalid login details", Toast.LENGTH_SHORT).show();                   
                        }
                    }
                }
            } catch (Exception e) {
                e.printStackTrace();
            }
            return null;
        }

**

这是我的PHP文件：

**

<?php
$db_host = "localhost";
$db_user = "root";
$db_password = "";
$db_name = "sample_login";
$response = array();
    $db_connect = mysql_connect($db_host, $db_user, $db_password) or die(mysql_error());
    $db = mysql_select_db($db_name);
    $eadd = $_POST['eadd'];
    $password = $_POST['password'];
    // mysql inserting a new row
    $result = mysql_query("SELECT * FROM users WHERE eadd = '$eadd' and password = '$password'");
    // check if row inserted or not
    if ($result) {
        // successfully inserted into database
        $response["success"] = 1;
        $response["message"] = "Login succes";
        // echoing JSON response
        echo json_encode($response);
    } else {
        // failed to insert row
        $response["success"] = 0;
        $response["message"] = "Oops! An error occurred.";
        // echoing JSON response
        echo json_encode($response);   
}
?>

**